According to the calculation, each visitor went down, on average, 11.41 times.
<h3><u>Averages</u></h3>
Given that a water park keeps track of the number of times each visitor goes down water slides during their visit, and 12 visitors went down a water slide 4, 22, 16, 10, 11, 20, 20, 12, 6, 3, 11 and 1 times, to determine the average number of times each visitor went down, the following calculation must be performed:
- (4 + 22 + 16 + 10 + 11 + 20 + 20 + 12 + 6 + 3 + 11 + 1) / 12 = X
- 137 / 12 = X
- 11.41 = X
Therefore, each visitor went down, on average, 11.41 times.
Learn more about averages in brainly.com/question/897199
A = 1/2(15+7+15+7)(13)
A= 1/2(44)(13)
A = 286
answer
286
The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:
If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper
Answer: We are given there are 49 cars
Also these 49 cars are in a line stretched 528 feet.
Now the average length of the car is:
Average length = 
=
Therefore, the average length of car is 10.78 feet
