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2 years ago

Please help me answer Question 1.

Chemistry

1 answer:

ratelena [41]2 years ago

7 0

Answer:

9 moles of oxygen are produced from 6 moles of potassium chlorate.

Explanation:

Given data:

Number of moles of KClO₃ = 6 mol

Number of moles of oxygen produced = ?

Solution:

Chemical equation:

2KClO₃ → 2KCl + 3O₂

now we will compare the moles of KClO₃ and O₂.

KClO₃ : O₂

2 : 3

6 : 3/2×6 = 9

Thus, 9 moles of oxygen are produced from 6 moles of potassium chlorate.

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Calculate the [OH-] given pH of 9.9

Juli2301 [7.4K]

Answer

pOH = 4.1

Explanation

Given:

pH = 9.9

Required: The concentration of OH-

Solution

pH + pOH = 14

9.9 + pOH = 14

pOH = 14-9.9

pOH = 4.1

3 0

1 year ago

How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)

Masteriza [31]

Answer: The amount of heat required to warm given amount of water is 470.9 kJ

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g$

To calculate the heat absorbed by the water, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(100-25)^oC=75^oC$

Putting values in above equation, we get:

$q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ$

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0

2 years ago

Please help with the question above!

Sergio [31]

Answer:

Explanation:

7 0

2 years ago

Read 2 more answers

Please help me to answer this question. i have to submit tomorrow.

ratelena [41]

Answer:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

4 0

3 years ago

Calculate the volume of 2.65 moles of N2O gas at STP.

Reptile [31]

Answer:

63.6 dm³

Explanation:

Volume of gas= no. of moles ×24dm³

Thus, volume of N₂O

= 2.65 × 24

= 63.6 dm³

3 0

3 years ago