Question

A cable is lifting a construction worker and a crate, as the drawing shows. The weights of the worker and crate are 965 N and 1510 N, respectively. The acceleration of the cable is 0.620 m/s2, upward. What is the tension in the cable(a) below the worker and(b) above the worker?

Answer 1

Answer:(a)2631.46 N

(b)1605.51 N

Explanation:

Assuming there is a cable between crate and worker

Given

weight of worker $W_w=965 N$

Weight of crate $W_c=1510 N$

mass of worker $m_w=\frac{965}{g}=98.46 kg$

mass of crate $m_c=\frac{1510}{g}=154.08 kg$

acceleration of system $a=0.620 m/s^2$

Tension in the wire carrying Worker

$T-(m_w+m_c)g=(m_w+m_c)a$

$T=(m_w+m_c)(g+a)$

$T=(252.54)(9.8+0.62)$

$T=2631.46 N$

(b)Tension in the string above

$T_2-m_c\cdot=m_ca$

$T_2=m_c(g+a)$

$T_2=154.08(9.8+0.62)$

$T_2=1605.51 N$