Answer:
Explanation:
Let the internal resistance be r .
Since in open circuit the volt is 1.55 V , this will be the source voltage .
Source voltage = 1.55
If external resistance be R .
1.55 / (R + r ) = .500
R + r = 3.1 ohm
So sum of internal resistance and external resistance will be 3.1 ohm.
Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.
<h3>What is Current?</h3>
Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.
If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;
I = Q/t
Where Q is the charge and t is time elapsed.
Given the data in the question;
- Time elapsed t = 1hr = 3600s
- Current I = 350mA = 0.35A
We substitute our given values into the expression above to determine the charge.
I = Q/t
Q = I × t
Q = 0.35A × 3600s
Q = 1260C
Therefore, given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.
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Below is the solution:
<span>centripetal accel = 1.5*g
ω²r = 1.5*9.8m/s²
ω² * 8m = 14.7 m/s²
ω = 1.36 rad/s * 1rev/2πrads * 60s/min = 12.9 rpm</span>
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