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3 years ago

What is the acceleration of Romeo’s 900 kg horse if it moves with a force of 9000 N?

Physics

1 answer:

stellarik [79]3 years ago

5 0

Answer:

Explanation:

a = F/m where a = acceleration, F = Force, and m = mass

a = 9000N/900kg

a = 10 m/s

Hope this helps!

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A forward horizontal force of 12n is used to pull a crate across a horizontal floor at a constant velocity. If the crate weighs

kow [346]

Explanation:

μ = coefficient of friction.

F = Frictional force = 12N

R = Normal reaction = mg = Weight = 240N

m = mass

g = acceleration due to gravity ≈ 9.8ms—²

μ = F/R

μ = 12/240

μ = ¹/20

μ = 0.05

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2 years ago

What is star wars 1313

Vinvika [58]

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3 years ago

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Who studies this branch of physics? What types of careers are there in this branch of physics? What particular subjects should s

kolezko [41]

The answers to all three questions depend on WHICH branch

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4 years ago

A freight car of mass M contains a mass of sand m. At t = 0 a constant horizontal force F is applied in the direction of rolling

Veronika [31]

Answer:

Amount of linear movement

Explanation:

Our system is defined by the rate of change in mass that

leaves the car $\Delta m_ {s}$ , this happens during a time interval

$[t, t + \Delta t]$ , in addition to freight car and sand at time t.

In this way we need to define the two states:

State 1,

consider $t, m_ {c} (t) + \Delta m_ {s}$ and V.

State 2,

consider $t + \Delta t, m_ {c} (t), V + V \Delta V$

In this state is the mass of sand output, which

is composed of

$\Delta m_{s}, V + \Delta V$

In this way we define the Linear movement in x, like this:

$p_ {x} (t) = (\Delta m_ {s} + m_ {c} (t)) v$

$p_ {x} (t+\Delta t) = (\Delta m_ {s} + m_ {c} (t)) (v + \Delta v)$

$m_ {c} (t) = m_ {c, 0} - bt = m_ {c} + m_ {s} -bt$

In this way we proceed to obtain the Force

$F =\lim_{\Delta t \rightarrow 0} \frac {p_x (t + \Delta t) -p_ {x} (t)} {\Delta t}$

$F = lim_{\Delta t \rightarrow 0} m_ {c} (t) \frac {\Delta v} {\Delta t} + lim_{\Delta t \rightarrow 0} m_ {s} (t) \frac {\Delta v} {\Delta T}$

Since the mass of the second term becomes 0, the same term is eliminated, thus,

$F = m_ {c} (t) \frac {dv} {dt}$

$\int\limit ^ {v (t)} _ {v = 0} dv = \int\limit^t_0 \frac{Fdt} {m_ {c} + m_ {s} -bt}$

$V (t) = - \frac {F} {b} ln (\frac {m_c + m_s-bt} {m_c + m_s})$

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3 years ago

According to Newton's first law, an object in motion will stay in motion unless:

Nadusha1986 [10]

Answer: unless it's acted upon by an external force

Explanation: Newton first law of motion State that an object will continue in it state of rest or in motion, unless it is been acted upon by an external force

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3 years ago