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marin [14]
3 years ago
6

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball

of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?
A) The balls are made of the same material.
B) The first ball is made of a material with a higher specific heat.
C) The second ball is made of a material with a higher specific heat.
D) The specific heat of one of the balls is two times that of the other.
Chemistry
2 answers:
Harrizon [31]3 years ago
7 0

Answer:

A. The balls are made of the same material

erica [24]3 years ago
6 0

Answer:

A) The balls are made of the same material.  

Explanation:

Q= m c delta T

where Q is heat, m is mass, c is specific heat capacity and delta T is the difference in temperature.  

When c and delta T are held constant, heat is directly proportional to the mass.  

Here  both the metal balls have the same delta T, and as the mass of the ball double so does the heat lost, this implies that both the balls are made up of the material and have the same specific heat capacity.  

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3 years ago
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How many grams of ice at -13 deg C must be added to 711 grams of water that is initially at a temperature of 87 deg C to produce
Basile [38]

Answer:

The answer to your question is m = 4.7 kg

Explanation:

Data

Ice                                   Water

mass = ?                          mass = 711 g

T₁ = -13°C                         T₁ = 87°C

T₂ = 10°C                         T₂ = 10°C

Ch = 2090 J/kg°K          Cw = 4180 J/kg°K

Process

1.- Convert temperature to kelvin

T₁ = 273 + (-13) = 260°K

T₁ water = 87 + 273 = 360 °K

T₂ = 10 + 273 = 283°K

2.- Write the equation of interchange of heat

                 - Heat lost = Heat absorbed

               - mwCw(T₂ - T₁) = miCi(T₂ - T₁)

-Substitution

              - 0.711(4180)(10 - 87) = m(2090)(10 - (-13))

- Simplification

                            228842.46 = 48070m

                            m = 228842.46/48070

-Result

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4 0
3 years ago
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(3) CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g) K_3=2.68\times 10^{-9}

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CO_2(g)\rightleftharpoons C(s)+O_2(g) K_{goal}=?

Now we have to calculate the value of K_{goal} for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

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