The correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
<h3>What are the functions of clean water regulation?</h3>
Clean Water Act (CWA) is a regulatory body that establishes the basic structure for the regulation of pollutants discharge and maintenance of quality standards of the surface waters.
On the other hand, the Safe Drinking Water Act was founded to oversee the protection of the quality drinking water. The regulatory body is primarily concerned with potable water all waters, whether from above ground or underground sources.
Therefore, the correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
Learn more about clean water regulation at: brainly.com/question/2142268
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We make use of the equation: v^2=v0^2+2a Δd. We substitute v^2 equals to zero since the final state is halting the truck. Hence we get the equation -<span>v0^2/2a = Δd. F = m a from the second law of motion. Rearranging, a = F/m
</span>F = μ Fn where the force to stop the truck is the force perpendicular or normal force multiplied by the static coefficient of friction. We substitute, -v0^2/2<span>μ Fn/m</span> = Δd. This is equal to
Answer:
yes
Explanation:
you will feel weary after shorter times
Answer:
Explanation:
First of all, we need to find the pressure exerted on the sphere, which is given by:
where
is the atmospheric pressure
is the water density
is the gravitational acceleration
is the depth
Substituting,
The radius of the sphere is r = d/2= 1.1 m/2= 0.55 m
So the total area of the sphere is
And so, the inward force exerted on it is
Answer:
F > W * sin(α)
Explanation:
The force needed for the box to start sliding up depends on the incline (α).
The external forces acting on the box would be the weight, the normal reaction and the lifting force that is applied to make it slide up.
These forces can be decomposed on their normal and tangential (to the slide plane) components.
The weight will be split into
Wn = W * cos(α) (in normal direction)
Wt = W * sin(α) (in tangential direction)
The normal reaction will be alligned with the normal axis, and will be equal to -Wn
N = -W* cos(α) (in normal direction)
To mke the box slide up, a force must be applied, that is opposite to the tangential component of the weight and at least a little larger
F > |-W * sin(α)| (in tangential direction)
