Question

A charge of 6. 4 × 10–7 C experiences an electric force of 1. 8 × 10–1 N. What is the electric field strength? 1. 1 × 10–7 N/C 3. 6 × 10–6 N/C 8. 2 × 100 N/C 2. 8 × 105 N/C.

Answer 1

The electric field strength is defined as the ratio of electric force and charge. The electric field strength will be 2.8 ×10⁵ N/C.

What is electric field strength?

The electric field strength is defined as the ratio of electric force and charge. The field's direction is determined by the direction of the force acting on the positive charge.

A positive charge produces a radially outward electric field, whereas a negative charge produces a radially inward electric field.

The given data in the problem is;

Q is the charge= 6. 4 × 10–7 C

E is the electric force=1. 8 × 10–1 N

The relation between the electrostatic force and the electric field due to a charge is given as:

$\rm F_E=Q E \\\\ \rm E=\frac{F_E}{Q} \\\\ \rm E=\frac{1.8\times 10^{-1}}{6.4\times 10^{-7}} \\\\ \rm E=2. 8 \times 10^5\ N/C.$

Hence the electric field strength will be 2.8 ×10⁵ N/C.

To learn more about the electric field strength refer to the link;

brainly.com/question/4264413