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padilas [110]
3 years ago
6

Which words describe the image below? CHECK ALL THAT APPLY.

Chemistry
2 answers:
3241004551 [841]3 years ago
3 0

Answer:

A) liquid

Explanation:

hope this helps you!!

QveST [7]3 years ago
3 0
Liquid

Explanation : In liquids, the particles are near each other, but not tightly packed. The particles in a liquid are able to slide past each other.

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The pka of hf is 3.2 determine the pkb of hf?
Julli [10]

Well, first we must remember that

pK_{a}+pK_{b}=14

This is because

K_{a}*K_{b}=10^{-14}

-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14

So then

pK_{b}=14-pK_{a}=14-3.2=1.8

7 0
4 years ago
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POV: You buy a composite cup at the store. Explain the reason for your decision.
Len [333]

Answer:

i bought it cuz i need a cup?

Explanation:

7 0
3 years ago
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Astrology, a belief in a relationship between constellations of stars and life events,
yanalaym [24]

Answer:

Pseudoscience

Explanation:

"Astrology has not demonstrated its effectiveness in controlled studies and has no scientific validity, thus regarded as pseudoscience."

3 0
3 years ago
How many molecules of BH3 are in 14.32 grams of BH3?
kkurt [141]

Answer:

6.23 x 10^23 molecules

Explanation:

First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.

We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.

Finally, to figure out the number of molecules, we multiply 1.03 by Avogadro's number which is 6.022x10^23 and we get 6.23x10^23 molecules.

3 0
3 years ago
What is the pressure of 1.20 moles of SO2 gas in a 4L container at 30 degrees celsius
geniusboy [140]
Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

                                       P V  =  n R T
Solving for P,
                                       P  =  n R T / V     ----- (1)
Data Given;

Moles  = n = 1.20 mol

Volume  = V =  4 L

Temperature  = T = 30 + 273 = 303 K

Gas Constant  = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

                     P  =  (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

                     P  =  7.45 atm
6 0
3 years ago
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