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arsen [322]
3 years ago
7

Students in Ms. Nye's science class were using the microscopes to make slides of various organisms: algae, moss, onion cells, hu

man cheek cells, as well as the organism seen here. They were examining cell structures to group the organisms by similarities. Several students grouped this organism with the plants they were examining because of the presence of cell walls. Another group argued: "This is a fungus not a plant, because the cells do not contain _____________."
Chemistry
2 answers:
galina1969 [7]3 years ago
8 0
The answer is chloroplast
Firlakuza [10]3 years ago
7 0

Answer:

c) Chloroplasts

Explanation: This is the correct answer on USA Test Prep

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bulgar [2K]
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3 years ago
PLEASE HELP ME YOU DONT HAVE TO DO WORK JUST TELL ME IF ITS RIGHT ON THE ORGANIC AND INORGANIC SIDE PLEASEE
Fittoniya [83]

Answer:

Its right you dont have to change anything

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3 years ago
you produce 115 grams of water in a combustion reaction. how much methane do you need in grams for this to react?
lora16 [44]

Answer:about 2 grams of methane

Explanation:

idk just got this right

6 0
3 years ago
4. Why can't the subscripts be changed in a chemical equation in chemistry
neonofarm [45]
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4 0
3 years ago
What compound is formed when methyloxirane (1,2-epoxypropane) is reacted with ethylmagnesium bromide followed by treatment with
Pavlova-9 [17]

Answer:

Pentan-2-ol

Explanation:

On this reaction, we have a <u>Grignard reagent</u> (ethylmagnesium bromide), therefore we will have the production of a <u>carbanion</u> (step 1). Then this carbanion can <u>attack the least substituted carbon</u> in the epoxide in this case carbon 1 (step 2). In this step, the epoxide is open and a negative charge is generated in the oxygen. The next step, is the <u>treatment with aqueous acid</u>, when we add acid the <u>hydronium ion</u> (H^+)  would be produced, so in the reaction mechanism, we can put the hydronium ion. This ion would be <u>attacked by the negative charge</u> produced in the second step to produce the final molecule: <u>"Pentan-2-ol".</u>

See figure 1

I hope it helps!

5 0
3 years ago
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