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jonny [76]
3 years ago
6

A golfer hits a ball at an angle of 12 degrees above horizontal. The velocity of the ball is 37 m/s. What is the horizontal dist

ance the ball travels in 2 seconds? A. 9.6 m B. 36 m C. 72 m D. 74 m
Physics
1 answer:
ruslelena [56]3 years ago
5 0

<u>72 m</u> is the horizontal distance the travels.

Option: C

<u>Explanation</u>:

The units to express the horizontal and vertical distances are meters (m). The "horizontal" and "vertical" velocities are expressed in "meters per second" (m/s).

Horizontal distance = (initial horizontal velocity)(time)

We can now get the range x from the horizontal component of velocity

x=v_{x o} \times t      equation (1)

\mathrm{v}_{\mathrm{xo}}=\text { initial horizontal velocity }(\mathrm{m} / \mathrm{s})

x = horizontal distance (m)

t = time (s)

\mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta

We know that, V = 37 m/s, θ = 12 degree and t = 2 seconds.

To find, \mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta

\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times \cos 12

\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times 0.974

\mathrm{V}_{\mathrm{x} \mathrm{o}}=36.038

\mathrm{Now}, \mathrm{x}=\mathrm{v}_{\mathrm{xot}}

x=36.038 \times 2

x = 72.076 m ~ 72 m

x = 72 m

The horizontal distance is <u>72 m.</u>

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