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Alenkasestr [34]
3 years ago
14

28. Someone throws a rubber ball vertically upward from the roof of a building 8.00 m in height. The ball rises,

Physics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

v_o= 12 m/s

Explanation:

The ball experienced a constant acceleration motion, so we need to apply the following formula:

y=y_o+v_o*t+\frac{1}{2}*a*t^2\\\\vo=\frac{y-y_o-\frac{1}{2}*a*t^2}{t}\\\\v_o=\frac{0m-8m-\frac{1}{2}*(-9.81m/s^2)*(3.00s)^2}{3.00s}\\v_o=12m/s

Note: we set the acceleration of gravity as negative because it is going down.

the ball was thrown vertically upward with an initial velocity of 12 m/s

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You can always calculate this right away, if you know his mass, by multiplying his weight in kg by the gravitational constant
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so, first step solved, Fg is 637.65N
Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
now let's calculate the force of the elevator
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so you draw another arrow which is pointing downwards on him, because the elevator is accelating him upwards, making him heavier
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