C sea water
l k. ,,.....................
Answer:
![V=9.89x10^{-7}\frac{L}{day}](https://tex.z-dn.net/?f=V%3D9.89x10%5E%7B-7%7D%5Cfrac%7BL%7D%7Bday%7D)
Explanation:
Hello,
On the attached document, you will find the procedure regarding the required volume. At first, it is necessary to know atoms by day produced, by using a rule of three. Subsequently, we compute the moles per day and finally the volume via the ideal gas equation at STP.
Best regards.
Hey there!:
<span>Reaction stoichiometry :
</span>
Number of moles NaHCO3 :
Molar mass NaHCO3 = <span>84.007 g/mol
</span>
n = m / mm
n = 2.50 / 84.007
n = 0.0297moles of NaHCO3
2 NaHCO3 + H2SO4 = Na2SO4 + 2 CO2 + 2 H2O
2 moles NaHCO3 ----------------- 1 mole H2SO4
0.0297 moles NaHCO3 ----------- moles H2SO4
moles H2SO4 = 0.0297 * 1 / 2
moles H2SO4 = 0.0297 / 2
= 0.01485 moles of H2SO4
Therefore:
Molarity ( H2SO4 ) = moles H2SO4 / volume
0.600 M = 0.01485 / V
V = 0.01485 / 0.600
V = 0.02475 L of H2SO4
hope this helps!
Answer:
![T_b=-88.48\°C](https://tex.z-dn.net/?f=T_b%3D-88.48%5C%C2%B0C)
Explanation:
Hello,
In this case, since the entropy of vaporization is defined in terms of the enthalpy of vaporization and the boiling point of the given substance, nitrous oxide, as shown below:
![\Delta _{vap}S=\frac{\Delta _{vap}}{T_b}](https://tex.z-dn.net/?f=%5CDelta%20_%7Bvap%7DS%3D%5Cfrac%7B%5CDelta%20_%7Bvap%7D%7D%7BT_b%7D)
Solving for the boiling point of nitrous oxide, we obtain:
![T_b=\frac{\Delta _{vap}H}{\Delta _{vap}S}=\frac{16.53\frac{kJ}{mol}*\frac{1000J}{1kJ} }{89.51\frac{J}{mol} } \\ \\T_b=184.67K](https://tex.z-dn.net/?f=T_b%3D%5Cfrac%7B%5CDelta%20_%7Bvap%7DH%7D%7B%5CDelta%20_%7Bvap%7DS%7D%3D%5Cfrac%7B16.53%5Cfrac%7BkJ%7D%7Bmol%7D%2A%5Cfrac%7B1000J%7D%7B1kJ%7D%20%7D%7B89.51%5Cfrac%7BJ%7D%7Bmol%7D%20%7D%20%5C%5C%20%5C%5CT_b%3D184.67K)
Which in degree Celsius is also:
![Tb=184.67-273.15\\\\T_b=-88.48\°C](https://tex.z-dn.net/?f=Tb%3D184.67-273.15%5C%5C%5C%5CT_b%3D-88.48%5C%C2%B0C)
Best regards.
The elements involved here are non-metals. The bond that forms between non-metals is a covalent bond where each atom shares one or more electron with the other so that both become stable. The number of shared electrons has to be equal for both.
Now, hydrogen needs only one electron to fill its outermost level and be stable and the same goes for fluorine, therefore, each of them shares one electron with the other.
Based on this, the answer would be:
<span>Hydrogen and fluorine share one electron with each other.</span>