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alekssr [168]
3 years ago
6

Wastewater discharged into a stream by a sugar refinery contains 1.70 g of sucrose (C12H22O11) per liter. A government-industry

project is designed to test the feasibility of removing the sugar by reverse osmosis. What pressure must be applied to the apparatus at 20.°C to produce pure water?
Chemistry
1 answer:
erik [133]3 years ago
5 0

Answer:

A pressure value more than 0.012 atm must be applied to the apparatus at 20.0°C to produce pure water.

Explanation:

When pressure more than the value of osmotic pressure of the solution is applied to the solution then water will move out from the solution which is termed as reverse osmosis.

Given that 1.70 grams of sucrose was present in 1 L of solution.

Moles of sucrose present in 1 liter of solution  = \frac{1.70 g}{342 g/mol}=0.004971 mol/L

C = 0.004971 mol/L

Temperature of the solution = T = 20.0°C = 20.0+273 K = 293 K

Osmotic pressure of soluion = \Pi

\Pi=CRT

\Pi=0.004971 mol/L\times 0.0821 atm L/mol K\times 293 K=0.012 atm

A pressure value more than 0.012 atm must be applied to the apparatus at 20.0°C to produce pure water.

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2 years ago
How are a flashlight and lightening similar and how are they different?
grandymaker [24]
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5 0
3 years ago
At a pressure of 782.3 mm Hg and 34.4 °C, a certain gas has a volume of 362.4 mL. What will
german

Answer: v2=331.289mL

Explanation:

Formula for ideal gas law is p1v1/T1=p2v2/T2

P1=782.3mmHg

P2=769mmHg at STP

V1=362.4mL

V2=?

T1=273+34.4=307.4k

T2=273k at STP

Then apply the formula and make v2 the subject of formula

V2= 782.3×362.4×273/760×307.4

V2=77397006.96/233624

V2=331.289mL

7 0
3 years ago
A container of oxygen with a fixed volume has a pressure of 13.0 atm at a temperature of 20 °C. What will the pressure of the ox
Norma-Jean [14]

Given:

P1 = 13.0 atm

T1 = 20 °C

T2 = 102 °C

Required:

P2 of oxygen

Solution:

At constant volume, we can apply Gay-Lussac’s law of pressure and temperature relationship

P1/T1=P2/T2

(13.0 atm) / (20 °C) = P2 / (102 °C)

P2 = 66.3 atm

The answer is not in the choices given.

6 0
3 years ago
450 nanometers to meters
lys-0071 [83]

Answer: 4.5 x 10e-7

Explanation: 450 x 1e+9 = correct answer

Multiply amount of nanometers by 1e+9 to get the approximate result in meters.

4 0
3 years ago
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