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alekssr [168]
3 years ago
6

Wastewater discharged into a stream by a sugar refinery contains 1.70 g of sucrose (C12H22O11) per liter. A government-industry

project is designed to test the feasibility of removing the sugar by reverse osmosis. What pressure must be applied to the apparatus at 20.°C to produce pure water?
Chemistry
1 answer:
erik [133]3 years ago
5 0

Answer:

A pressure value more than 0.012 atm must be applied to the apparatus at 20.0°C to produce pure water.

Explanation:

When pressure more than the value of osmotic pressure of the solution is applied to the solution then water will move out from the solution which is termed as reverse osmosis.

Given that 1.70 grams of sucrose was present in 1 L of solution.

Moles of sucrose present in 1 liter of solution  = \frac{1.70 g}{342 g/mol}=0.004971 mol/L

C = 0.004971 mol/L

Temperature of the solution = T = 20.0°C = 20.0+273 K = 293 K

Osmotic pressure of soluion = \Pi

\Pi=CRT

\Pi=0.004971 mol/L\times 0.0821 atm L/mol K\times 293 K=0.012 atm

A pressure value more than 0.012 atm must be applied to the apparatus at 20.0°C to produce pure water.

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A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
3 years ago
The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained
My name is Ann [436]

Answer:

4.75 moles of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

FeO + CO —> Fe + CO2

Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:

From the balanced equation above,

1 mole of FeO reacted to produce 1 mole of Fe.

Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.

Therefore, 4.75 moles of Fe is produced.

4 0
3 years ago
The _________ indicates that 70% of the Sun's radiation is contained on Earth and 30% is reflected back into space.
vichka [17]

i think it would be  Earth's albedo hope this helps

4 0
3 years ago
Read 2 more answers
(ii) Electrons are supplied to the external circuit. How and where is this done?<br> [2]
pentagon [3]

Answer:

The electrons are supplied by the species getting oxidized. They move from anode to the cathode in the external circuit. The external battery supplies the electrons. They enter through the cathode and come out through the anode

7 0
3 years ago
What is the molarity of a solution composed
Neporo4naja [7]

Answer:

0.0845 M

Explanation:

First we <u>convert 4.27 grams of potassium iodide into moles</u>, using its <em>molar mass</em>:

  • Molar Mass of KI = 166 g/mol
  • 4.27 g ÷ 166 g/mol = 0.0257 mol

Now we <u>calculate the molarity of the solution</u>, using <em>the number of moles and the given volume</em>:

  • Molarity = moles / liters
  • Molarity = 0.0257 mol / 0.304 L = 0.0845 M
7 0
3 years ago
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