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zepelin [54]
4 years ago
11

Jasper and Gemma are going to play on a teeter totter. Gemma gets on first. When Jasper gets on, Gemma moves into the air, but s

he does not move to the top. Which statement could correctly explain the forces acting on the teeter totter? The forces are balanced because Jasper weighs the same as Gemma. The forces are unbalanced because Jasper weighs the same as Gemma. The forces are balanced because Jasper weighs more than Gemma. The forces are unbalanced because Jasper weighs more than Gemma.
Physics
2 answers:
alexdok [17]4 years ago
4 0
The answer is A- The forces are balanced because Jasper weights the same as gemma.
slavikrds [6]4 years ago
3 0
The forces are unbalanced because Jasper weighs more than Gemma

The side that Gemma is on will only move upwards if the force exerted on the other side is greater than the force exerted by Gemma. In this case, force is referring to the weight of the children. Therefore, in order for Gemma to go upwards, Jasper must weigh more than her.
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How much tension is in a rope if it pulls a 5-kg bucket filled with water with an upward acceleration of 1m/s^2
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Read 2 more answers
A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block
MariettaO [177]

Answer:

v₀ = 0.5058 m/s

Explanation:

From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m

Now, the potential energy of the block at x = 0.08 m is ½kx²

where;

k is the spring constant given by; k = ω²m

ω is the angular velocity of the oscillation

m is the mass of the block.

Thus, potential energy of the spring at the bottle(x = 0.08 m) is;

U = ½ω²m(0.08m)²

Also, potential energy of the spring at the bottle(x = 0.05 m) is;

U = ½ω²m(0.05m)²

and the kinetic energy of the block at x = 0.05 m is;

K = ½mv₀²

Thus;

½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²

Inspecting this, ½m will cancel out to give;

ω²(0.08)² = ω²(0.05)² + v₀²

Making v₀ the subject, we have;

v₀ = ω√((0.08)² - (0.05)²)

So,

v₀ = 8.1√((0.08)² - (0.05)²)

v₀ = 0.5058 m/s

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3 years ago
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