Yes, it do, for a short time.
Answer:
The right solution is "0.50 m/s²". A further explanation is provided below.
Explanation:
The given values are:
Mass,
m = 50 kg
Speed,
v = 10 m/s
Rolling friction acting backward (south),
f = 10 N
Air resistance acting backward (south),
= 15 N
The total force acting will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
Now,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
The horizontal acceleration will be "0.50 m/s²" because the (-)ve sign indicates it in south direction.
Answer:
L = 0.44 [m]
Explanation:
Here we can use the Lorentz transformation related to length to solve it:

<u>Where</u>:
L₀ is the length of the moving reference frame (penguin #1)
L is the length of the fixed reference frame (penguin #2)
β is the ratio between v and c
<u>We know that v = 0.9c so we can find β.</u>

![L=1 [m]\sqrt {1-0.9^{2}} = 0.44 [m]](https://tex.z-dn.net/?f=L%3D1%20%5Bm%5D%5Csqrt%20%7B1-0.9%5E%7B2%7D%7D%20%3D%200.44%20%5Bm%5D%20)
Therefore, the length of the meter stick of #1 observed by #2 is 0.44 m.
I hope it helps you!