I’m pretty sure it is an object with a net force of zero. All forces are balanced and EQUAL
Answer:
During its trajectory the cannon ball will have kinetic and potential energy
E = KE + PE
The maximum value of PE will occur when the cannon ball was fired straight up - for other trajectories PE will be less because of translational KE
So E = M g h = 1/2 M v^2 for maximum height
h = v^2 / (2 * g) = 400 / (2 * 9.8) = 20.4 m
It is because earths mass is very large so its movement isnt noticibale
-- Bob covered a distance of (32m + 45m) = 77 meters.
-- His displacement is the straight-line distance and direction
from his starting point to his ending point.
The straight-line distance is
D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters
The direction is the angle whose tangent is (32/45) south of east.
tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
Average <u>speed</u> = (distance covered) / (time to cover the distance) =
(5m) / (15 sec) =
(5/15) (m/s) = <em>1/3 m/s</em> .
Average <u>velocity</u> =
(displacement) / (time spent traveling) in the direction of the displacement
Average velocity = (5m) / (15 sec) left =
(5/15) / (m/sec) left =
<em>1/3 m/s left</em>.
A number without a direction is a speed, not a velocity.