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dangina [55]
3 years ago
7

Which components of the apparatus affect in motion? If you answer this and it has non to do with the question imma report u!!!!

Chemistry
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

Explanation:

An internal force acts between elements of the system. Only external forces affect the motion of a system, according to Newton's first law. Newton's second law states that a net force on an object is responsible for its ... Prior to manned space flights, rocket sleds were used to test aircraft, missile equipment, and physiological

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Calculate the concentration 3.8g of copper sulfate, CuSO4 dissolved in 250cm4 of water
11Alexandr11 [23.1K]

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of copper sulfate = 3.8 g

Volume of water = 250 cm³  (250/1000 = 0.25 L)

Concentration of solution = ?

Solution:

Number of moles of copper sulfate:

Number of moles = mass/molar mass

Number of moles = 3.8 g/ 159.6 g/mol

Number of moles = 0.02 mol

Concentration:

Molarity = Number of moles / volume in L

By putting values,

Molarity = 0.02 mol / 0.25 L

Molarity = 0.08 mol/L

Molarity = 0.08 M

6 0
3 years ago
Which of the following carbon-based molecules stores information
Eduardwww [97]

The following carbon-based molecules store information are found in living things.

All organism are made of 4 type of carbon-based= carbon hydrate, lipids, proteins, and nuclear acid

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3 years ago
What is 4.25L to cm^3 ??
sasho [114]

Answer:

Explanation:

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3 0
4 years ago
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How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?
Murrr4er [49]
For every 2 moles of Li3N, you need 1 mole of N2
so for 0.08 mol Li3N, you need 0.04 moles N2
3 0
3 years ago
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A 5-kg quantity of radioactive isotope decays to 2 kg after 10 years. Find the decay constant of the isotope.k = _____
Dvinal [7]

Answer:

k = -0.09165 years^(-1)

Explanation:

The exponential decay model of a radioactive isotope is generally given as;

A(t) = A_o(e^(kt))

Where;

A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years

We are given;

A_o = 5 kg

A(10) = 2kg

t = 10 years

Thus;

A(10) = 2 = 5(e^(10k))

Thus;

2 = 5(e^(10k))

2/5 = (e^(10k))

0.4 = (e^(10k))

In 0.4 = 10k

-0.9164 = 10k

k = -0.9164/10

k = -0.09165 years^(-1)

7 0
3 years ago
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