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3 years ago

A pressure of 760.0 mm hg is equal to

Chemistry

1 answer:

evablogger [386]3 years ago

8 0

Answer:

760=101325

Explanation:

for an opproximate result,multiply the pressure value by 133

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6 How many moles are in a 321 g sample of magnesium?

Tatiana [17]

Answer:

13.4mol of Mg

Explanation:

Given parameters:

Mass of magnesium = 321g

Unknown:

Number of moles = ?

Solution:

The number of moles of a substance is given as;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Mg = 24g/mol

Insert the parameters and solve;

Number of moles = $\frac{321}{24}$ = 13.4mol of Mg

3 0

2 years ago

Which of these mixtures is a suspension?

natita [175]

Answer:

D. apple juice

Explanation:

8 0

2 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago

Please answer fast, shouldn't take long to do ^-^ (will give brainliest)

Anna [14]

Answer:

Explanation:

5 0

3 years ago

Which solid conducts electricity most efficiently?

irina1246 [14]

We see that is the <em>structure </em>of graphite it possess these attributes.

Graphite

Option A

<h3>Electricity</h3>

Generally, he conduction of electricity is do by elements with free talent electron after bonding.

Therefore, it is save to say that the <em>solid </em>that possess the attributes that allows for conduction will end up conducting.

Hence, we see that is the <em>structure </em>of graphite it possess these attributes.

Graphite

Option A

For more information on Electricity visit

brainly.com/question/9383604

4 0

2 years ago