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Georgia [21]
3 years ago
7

What is 2 x 1 + 2 x 24/4 help I will mark good

Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer: 16

Step-by-step explanation:

We follow BIMDAS.

So it becomes :

2+2×24/4 after the first step.

Then, 4+48/4

Then, 4+12

Which is 16

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Which is the area of a rectangle with a length of 21 feet and a width of 15 feet
muminat

Answer:

315 ft^2

Step-by-step explanation:

6 0
3 years ago
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Given H(6,7) and I (-7,-6) if point G lies 1/2 of the way long line segment HI, Santiago argues that point G is located at the o
amid [387]
A point that is half way of line segment is the midpoint

Let (6, 7) be (x₁, y₁) and (-7, -6) be (x₂, y₂)

Mid point of HI = (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2})
Mid point of HI = (\frac{6+-7}{2},  \frac{7+-6}{0})
Mid point of HI = (- \frac{1}{2} ,  \frac{1}{2})

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4 0
3 years ago
Plz help I don't know how to salve the question
kvv77 [185]

Answer:

24

Step-by-step explanation:

4 0
2 years ago
Find the area of the triangle be sure to include the correct unit in your answer
Vlad1618 [11]

Answer:

120 cm squared

Step-by-step explanation:

Area \:of \:the\: triangle  \\ =  \frac{1}{2}  \times base \times height \\  \\  =   \frac{1}{2}  \times 10 \times 24 \\  \\  = 12 \times 10 \\  \\  = 120 \:  {cm}^{2}

7 0
3 years ago
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Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
2 years ago
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