They share four electrons, two from each oxygen atom
Answer:
The answer is 3-Phenylpropanoic acid (see attached structure)
Explanation:
From spectral data:
3005 cm-1 ⇒ carboxylic acid (broad band)
1670 cm-1 ⇒ C=C
1603 cm-1 ⇒ Aromatic C-C bond
H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).
Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.
Thickness of cooper sheet is 0.048 cm (Approx.)
Given that;
Density of copper = 8.96 g/cm³
Measures of copper sheet = 5.5 cm × 5.5 cm
Mass of of copper sheet = 12.96 gram
Find:
Thickness of cooper sheet
Computation:
Volume = Mass / Density
Volume of cooper = 12.96 / 8.96
Volume of cooper = 1.4464
Volume of cooper = 1.45 cm³ (Approx.)
Volume of cooper sheet = 5.5 cm × 5.5 cm x Thickness
5.5 cm × 5.5 cm x Thickness = 1.45
Thickness of cooper sheet = 0.04793
Thickness of cooper sheet = 0.048 cm (Approx.)
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Answer is: Cl and Na.
sodium and chlorine are in third period and they have very different properties. Sodium is solid metal and chlorine is gaseous nonmetal.
They form compound NaCl (Sodium chloride), because sodium lost one valence electron and form cation Na⁺, chlorine gain one electron and form anion Cl⁻.
Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.
Electron configuration of chlorine atom: ₁₇Cl 1s² 2s² 2p⁶ 3s² 3p⁵.
Other examples are metal-metal pairs and they do not form cation and anion.
8E24/6.022E23= 13.28 moles, where the denominator is Avagadro's number
