Gauss’ law: a. Relates the surface charge density to the electric field.b. Relates the electric field at points on a closed surf
1 answer:
You might be interested in
Answer:
A. The wires will be arranged in order of increasing resistance.
Explanation:
The resistance of a wire is given by
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
In this problem we have several wires made of the same material (so, same ) and same length (same L): so, the only quantity that changes is their thickness, so their value of A.
We see from the formula that the resistance R is inversely proportional to the cross-sectional area A: therefore, the smaller the value of A, the larger the value of R. This means that if we arrange the wires in order of decreasing thickness, we are arranging the wires in order of increasing resistance.