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tensa zangetsu [6.8K]
3 years ago
11

Find the number if 12% of it is 10% of 6

Mathematics
2 answers:
qaws [65]3 years ago
6 0
10% of 6= 0.6

0.6 x 12= 7.2
drek231 [11]3 years ago
3 0

Let the number be x

So 12% of x

= 0.12 of x

= 0.12x

Also 10 % of 6

= 0.10 of 6

= 0.10 ×6

= 0.6

Now 12% of x is the same as 10% of 6.

So

Now as both represent the same quantity

So 0.12x = 0.6

Dividing both sides by 0.12

We get

x = 0.6 / 0.12

x= 5

Hence 12% of 5 is the same as 10% of 6

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In Exercises 6 and 7, use the given measure to find the missing value in each data set. 6. The mean of the ages of 5 brothers is
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Solution

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For this case we can do this:

12, 16,__, 14, 8, 7

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10 months ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
2 years ago
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