R=ρ l/a
l=5 cm
a=0.10 cm²
ρ=1.77×10∧-6 Ωcm
R=(1.77×10∧-6) ×5/0.10
=8.85 ×10∧-5 Ω
resistance is directly proportional to length and inversly proportional to area of cross section is given by above equation
The objects must be in physical contact. Convection is thermal energy transferred by the flow of matter. Radiation is the transfer of energy by electromagnetic radiation. ... 4.3: Thermal conductivity K is a constant indicating how easily heat is transferred through a substance. Sorry if I’m wrong.
Answer:
Explanation:
Let assume that system is conservative. From application of the Principle of Energy Conservation, it is noticed that initial linear kinetic energy must be equal to the gravitational energy at the top of the circle. That is to say:
Where .
Answer:
ω = 3.66 rad/s
Explanation:
Given that
L= 1 m
M = 270 g = 0.27 kg
m = 3 g
u= 250 m/s
v= 140 m/s
We know that moment of inertia of the rod about it center
I=0.0225 kg.m²
The initial angular momentum
L₁ = m u r
Final angular momentum
L₂= I ω+m v r
Here r= L/4
r= 0.25 m
There is no any external torque ,it means that angular momentum will be conserve
L₁ = L₂
m u r = I ω+m v r
m r (u - v)=I ω
Now by putting the values
m r (u - v)=I ω
0.003 x 0.25 x (250- 140)=0.0225 x ω
ω = 3.66 rad/s
Answer:
8.25 V
Explanation:
We can ignore the 22Ω and 122Ω resistors at the bottom. Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.
The 2Ω resistor and the 44Ω resistor are in parallel. The equivalent resistance is:
1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω
This resistance is in series with the 12Ω resistor. The equivalent resistance is:
1.913Ω + 12Ω = 13.913Ω
This resistance is in parallel with the 24Ω resistor. The equivalent resistance is:
1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω
Finally, this resistance is in series with the 4Ω resistor. The equivalent resistance of the circuit is:
8.807Ω + 4Ω = 12.807Ω
The current through the battery is:
12 V / 12.807Ω = 0.937 A
The voltage drop across the 4Ω resistor is:
(0.937 A) (4Ω) = 3.75 V
So the voltage between the bottom nodes and the top nodes is:
12 V − 3.75 V = 8.25 V