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sweet-ann [11.9K]
3 years ago
12

What would happen if the parent cell were to divide more times than usual during mitosis

Physics
1 answer:
SCORPION-xisa [38]3 years ago
4 0

Answer:

Mitosis is a type of cell division in which a parent cell divides into two identical daughter cells, each with the same number and kind of chromosomes as the parent cell.

When a parent cell divides more times than usual during mitosis, the division of chromosomes between the chromosomes would not be proper. For example, a daughter cell may end up with one chromosome less than the parent cell. This ultimately results in genetic disorders.

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A sky diver, mass 90 kg, reaches a terminal velocity of 60 m/s. What is the approximate magnitude of the force of air resistance
Komok [63]

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The approximate magnitude of the force of air resistance is 540 N.

Explanation:

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a force of 20 n is directed at an angle of 609 above the x-avis. a second force of 20 n is directed at an angle of 60 below the
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20 N , in +x direction is the vector sum of these Toro forces.

<h3>What is force?</h3>
  • The word "force" has a specific meaning in science.
  • At this level, calling a force a push or a pull is entirely appropriate.
  • A force is not something an object "has in it" or that it "contains."
  • One thing experiences a force from another.
  • There are both living things and non-living objects in the concept of a force.
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  • The newton, abbreviated N, is the SI unit of force.

To learn more about forces from the given link :

brainly.com/question/28021338

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7 0
2 years ago
If an atom has a mass number of 23, which of the following is always true?
WINSTONCH [101]
The number of protons in the nucleus does not equal the number of nuetrons
6 0
3 years ago
A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en
Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

(c) 4.71 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

-\frac{dU}{dx}=F\\ dU=-Fdx

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

U=\frac{-7}{2}x^{2} + 11x + c

we know that U is equal to 26 J when x is zero, so:

U=\frac{-7}{2}x^{2} + 11x + c

26=\frac{-7}{2}(0)^{2} + 11(0) + c

26=c

Finally, the equation for the potential energy is:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}

Where b is the number beside x and a is the number beside x^{2}, Then, the value of maximum U is:

U(11/7)=\frac{-7}{2}(11/7)^{2} + 11(11/7) + 26

U(11/7)=34.6429J

On the other hand, the negative and positive values of x where the potential energy is equal to zero is calculated as:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

0=\frac{-7}{2}x^{2} + 11x + 26

if we solve this using the quadratic equation, we get:

x =\frac{-11+\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=-1.5747

x =\frac{-11-\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=4.7175

Finally, the negative and positive values of x where the potential energy is equal to zero are -1.5747 and 4.7175 respectively.

3 0
3 years ago
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