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3 years ago

Compare the densities of two objects that have the same volume, but one feels heavier than the other. Please help

2 answers:

8 0

If both objects have the same volume, but a different weight, than the densities are different. One has the greater density, while the other doesn't.

podryga [215]3 years ago

6 0

Explanation:

Density of a substance is defined as mass divided by its volume.

Mathematically, Density = $\frac{mass}{volume}$

So, density is proportional to the mass of substance. Hence, an increase in mass will lead to increase in density of the substance also.

Whereas density is inversely proportional to volume of a substance. Hence, an increase in volume will lead to a decrease in density of the substance.

So, when densities of two objects that have the same volume, but one feels heavier than the other then it means mass of one object is greater than the other.

Hence, density of one object is greater than the other. That is why, one feels heavier than the other.

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3 years ago

Put the following names in the correct alphabetic indexing order:(1) Topper & Casey Plumbing(2) KST Enterprises(3) Leland an

dangina [55]

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5 0

3 years ago

Read 2 more answers

Aluminium sulfate hydrate al2(so4)3.xh2o contains 13.63% al by mass. calculate x, that is, the number of water molecules associa

Advocard [28]

MAl₂(SO₄)₃·xH₂O:
(mAl×2) + (mS×3) + (mO×12) + (mH₂O×x)
(27×2)+(32×3)+(16×12)+(x×18) = 342 + 18x [g]
mAl₂: 27×2 = 54 [g]

54g ---------- 13,63%
342+18x ---- 100%
0,1363(342+18x) = 54
46,6146 + 2,4534x = 54
2,4534x = 7,3854
x ≈ 3

>>> Al₂(SO₄)₃·3H₂O <<<<
:)

8 0

3 years ago

Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Comple

AfilCa [17]

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.

Symbol of an alpha particle is $^{4}_{2}\alpha$ . Whereas a neutron is represented by a symbol $^{1}_{0}n$ , that is, it has zero protons and only 1 neutron.

Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

$^{27}_{13}Al + ^{1}_{0}n \rightarrow ^{30}_{15}P + ^{1}_{0}n$

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3 years ago