<h2>The intensity at a distance of 4.5 cm is 68.9 N/C</h2>
Explanation:
The electric field intensity on the surface of cylinder E₁ = λ/2πε₀R I
here λ is the charge density of cylinder
R is the radius of cylinder
and 1/2πε₀ is a constant of permitiivity
Similarly the intensity at a distance r from center of cylinder
E₂ = λ/2πε₀r II
Dividing II by I , we have
E₂/E₁ = R/r
here E₁ = 155 N/C
R = 2.0 cm and r = 4.5 cm
Substituting , the value
E₂/155 = 2/4.5
or E₂ = x 155 = 68.9 N/C
( b ) Because E = - dV/dr
Here V is the potential at a point
Thus V = -
Here E = λ/2πε₀r and b = 2cm and a = 4.5 cm
Thus VB - VC = λ/2πε₀ [ log4.5 - log2 ]
( c ) The potential at points A and B is the same .
Thus VA - VB = 0