Answer:
130 km at 35.38 degrees north of east
Explanation:
Suppose the HQ is at the origin (x = 0, y = 0)
So the coordinates of the helicopter after the 1st flight is


After the 2nd flight its coordinate would be:


So in order to fly back to its HQ it must fly a distance and direction of
north of east
Inertia depends on mass, the more mass the more inertia.
U = 0, initial upward speed
a = 29.4 m/s², acceleration up to 3.98 s
a = -9.8 m/s², acceleration after 3.98s
Let h₁ = the height at time t, for t ≤ 3.98 s
Let h₂ = the height at time t > 3.98 s
Motion for t ≤ 3.98 s:
h₁ = (1/2)*(29.4 m/s²)*(3.98 s)² = 232.854 m
Calculate the upward velocity at t = 3.98 s
v₁ = (29.4 m/s²)*(3.98 s) = 117.012 m/s
Motion for t > 3.98 s
At maximum height, the upward velocity is zero.
Calculate the extra distance traveled before the velocity is zero.
(117.012 m/s)² + 2*(-9.8 m/s²)*(h₂ m) = 0
h₂ = 698.562 m
The total height is
h₁ + h₂ = 232.854 + 698.562 = 931.416 m
Answer: 931.4 m (nearest tenth)
Answer:
The current in the coil is 60 Ampere.
Explanation:
Given:
Number of turns in the coil is N = 25
Dimension of the coil = 15cm X 12cm
magnitude of magnetic field = 0.20T
angle in the xy plane is θ = 0 degree
torque τ = 5.4 N-m
To find:
current in the coil is i = ?
Solution:
The torque acting on the coil is given by
=> 
Converting cm to m
12 cm = 0.12 m
15 cm = 0.15 m
The area of the coil is
A = 0.12 X 0.15
A = 
Substituting the values
=>
=>
=>
=>
=>
=>
=> i = 60 A