Ask question

Ask question

All categories

2 years ago

7

Which type(s) of subatomic particles can be located within the nucleus of an atom?

1 answer:

blagie [28]2 years ago

6 0

According to the research, the correct option is c. Protons and neutrons are subatomic particles can be located within the nucleus of an atom.

<h3>What is an atom?</h3>

It is the minimum unit of a substance, which makes up all common matter and is made up of a nucleus with protons and neutrons and several orbital electrons, the number of which varies according to the chemical element.

In this sense, protons are subatomic particles that have a positive energetic charge, while neutrons have no charge.

Therefore, we can conclude that according to the research, the correct option is c. Protons and neutrons are subatomic particles can be located within the nucleus of an atom.

Learn more about an atom here: brainly.com/question/11467887

#SPJ1

You might be interested in

Which of the following is not part of testing a hypothesis?

Natasha2012 [34]

Isn't a hypothesis making a theory? Based on that I guess the answer would be A. Making a theory, because you making the hypothesis is not part of testing it.

3 0

4 years ago

Read 2 more answers

If you double the pressure on the surface of a can of water, the buoyant force on a stone placed in that water will

Bingel [31]

The buoyant force won't change.

4 0

4 years ago

Choose the answer to fill in the blank, which best completes the sentence.

Allisa [31]

Answer:

A on edge 2020

Explanation:

4 0

3 years ago

Read 2 more answers

(a) Calculate the force (in N) needed to bring a 1100 kg car to rest from a speed of 85.0 km/h in a distance of 125 m (a fairly

nasty-shy [4]

(a) -2451 N

We can start by calculating the acceleration of the car. We have:

$u=85.0 km/h = 23.6 m/s$ is the initial velocity

v = 0 is the final velocity of the car

d = 125 m is the stopping distance

So we can use the following equation

$v^2 - u^2 = 2ad$

To find the acceleration of the car, a:

$a=\frac{v^2-u^2}{2d}=\frac{0-(23.6 m/s)^2}{2(125 m)}=-2.23 m/s^2$

Now we can use Newton's second Law:

F = ma

where m = 1100 kg to find the force exerted on the car in order to stop it; we find:

$F=(1100 kg)(-2.23 m/s^2)=-2451 N$

and the negative sign means the force is in the opposite direction to the motion of the car.

(b) $-1.53\cdot 10^5 N$

We can use again the equation

$v^2 - u^2 = 2ad$

To find the acceleration of the car. This time we have

$u=85.0 km/h = 23.6 m/s$ is the initial velocity

v = 0 is the final velocity of the car

d = 2.0 m is the stopping distance

Substituting and solving for a,

$a=\frac{v^2-u^2}{2d}=\frac{0-(23.6 m/s)^2}{2(2 m)}=-139.2 m/s^2$

So now we can find the force exerted on the car by using again Newton's second law:

$F=ma=(1100 kg)(-139.2 m/s^2)=-1.53\cdot 10^5 N$

As we can see, the force is much stronger than the force exerted in part a).

8 0

3 years ago

A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound

NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

$f_n=\frac{nv_s}{4L}$

n: number of the harmonic = 3

vs: speed of sound = 340 m/s

L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

$f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz$

hence, the frequency of the third overtone is 102 Hz

8 0

3 years ago