For a pipe open at both ends, fund frequency (Fo) given byFo = v /2L
v = velocity of sound = 340 m/s (at about 20ºC)
Fo = 340/2*5.34 = 31.8 Hz
While for the one closed at one end and open at the other end...
For a pipe open at one end, fund frequency (Fo) given byFo = v/4L
Fo = 340/4*5.34= 15.9 Hz
Answer: (a) B = 2 x 10⁻⁵T
(b) B = 1.94 x 10⁻⁵T
(c) B = 1.8 x 10⁻⁴T
Explanation: A magnetic field due to a current passing through a straight wire is calculated using the <u>Biot-Savart</u> <u>Law</u>:

where
dL is current length element
is permeability of free space (
T.m/A)
(a) For a infinite straight wire:


B = 2x10⁻⁵T
For an infinite, long and straight wire, magnetic field is 2x10⁻⁵T.
(b) For a finite wire:


B = 1.94x10⁻⁵T
The magnetic field for a finite wire in the same conditionsas infinite wire is 1.94x10⁻⁵T.
(c) For a finite wire at a point distant from the end of the wire:


B = 0.18x10⁻⁵T
At a point at the end, magnetic field is 1.8x10⁻⁴T.
Answer; Resonance is an increase in amplitude of a vibration that occurs when external vibrations match an object's natural frequency. The Tacoma Narrows Bridge may have collapsed because of resonance.
Explanation:
We dont have the powerpoint
The answer is mass
So when the mass decreases the acceleration increases