The actual answer is 165 miles, but using significant figure rules the answer is 200. This is because the sig fig rules are as follows ...
<span>1. Non-zero digits are always significant.
2. Any zeros between two significant digits are significant.
<span>3. A final zero or trailing zeros in the decimal portion ONLY are significant.
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So the zeroes in a number like 20 or 23,000 are NOT significant. When you add numbers you must find the addend with the lowest amount of significant figures and round the answer to that. In this case most of the addends only have one sig fig, so you round 165 to 200 to make it only have one sig fig.
Answer:
Final speed, v = 28.81 m/s
Explanation:
Given that,
Mass of the car, m = 1423 kg
Initial speed of the car, u = 26.4 m/s
Force experience by the car, F = 901 N
Distance, d = 106 m
To find,
The speed of the car after traveling this distance.
Solution,
The force experienced by a car is equal to the product of mass and acceleration.
Let v is the final speed of the car. Using third equation of motion to find it as :
v = 28.81 m/s
So, the final speed of the car is 28.81 m/s.
Answer:
A. Two strands of nucleotides bonded together at their bases,
twisting to form a double helix
Explanation:
Hope this helps! Can I have brainliest?
Answer:
d. may be either greater, smaller, or equal to that observed inside the bus.
Explanation:
- The bus is moving at a constant speed. The ball tossed and received by the ball is inside the bus at a speed equal to the speed of the ball. Therefore the speed of the bus becomes zero with respect to the observer inside the bus.
- Now the observer inside the bus noticed the ball from the inside of the bus, so he threw the ball back and forth from the ball with the speed v relative to the observer.
- Now the observer outside the bus could see the bus moving at speed relative to its reference point and also throwing the ball from front to back. The speed of the ball to the observer outside the bus The speed of the bus to the observer outside the bus is minus the speed of the ball to the observer inside the bus.
- Therefore, the ball speed = (u-v) relative to the observer outside the bus.
