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Annette [7]
3 years ago
7

GIVING BRAINLIEST Which statement best explains how Earth's magnetic field is generated? Earth's core spins slower than its crus

t Heat exchange between the mantle and crust The convection of heat within the mantle Rotation of liquid iron in the outer core
Physics
1 answer:
zimovet [89]3 years ago
8 0

Answer:

The convection of heat within the mantle Rotation of liquid iron in the outer core

Explanation:

The electrical currents and convecting movements within the Earth's liquid core generate the planet's powerful magnetic field, which in turn drives the inner core in the way that can now be observed.

You might be interested in
A solid ball of radius rb has a uniform charge density rho.
Oksana_A [137]

Note: question B is incomplete.

Complete Question

A solid ball of radius rb has a uniform charge density ρ.

a.  What is the magnitude of the electric field E(r) at a distance r>rb from the center of the ball?  Express your answer in terms of ρ, rb, r, and ϵ0.

b.   What is the magnitude of the electric field E(r) at a distance r<rb from the center of the ball?  Express your answer in terms of ρ, r, rb, and ϵ0.

c.   Let E(r) represent the electric field due to the charged ball throughout all of space. Which of the following statements about the electric field are true?

1. E(0) = 0.

2. E(rb) = 0

3. lim E(r) = 0.

4. The maximum electric field occurs when r = 0.

5. The maximum electric field occurs when r = rb.

6. The maximum electric field occurs as r to infinity.

Answer:

a) the magnitude of E(r)= ρr³/3 ε₀r²

b) the magnitude at distance r from the centre E(r)= ρr/3 ε ₀ ( if r<rb)

c) statements 1(E(0) = 0), 3(E(0) = 0) and 5(The maximum electric field occurs when r = rb.) are true

Explanation:

given

charge density = ρ ,  ε

Volume of sphere , V = (⁴/₃)πr³

a) charge density = charge/volume

ρ = q ÷ V

make charge the subject of the formula

∴q = ρ × V=  ρ× (⁴/₃)πr³

where r³ = rb³(at distance rb³)

recall

E= q/4πε₀r²

E=  ρ × (⁴/₃)πrb³/4πε₀r²

∴E(r)= ρrb³/3 ε ₀r²

(b)  The Gaussian surface is inside the ball, therefore, surface only encloses a portion of ball's charge .

The net charge enclosed by the Gaussian surface is different to the of net charge enclosed in (a)

Recall

E= q/4πε₀r²

V= (⁴/₃)πr³

E=  ρ × (⁴/₃)πr³/4πε₀r²

∴E(r)= ρr/3 ε₀

(c)  E(0)= 0

limr-----∝

E(r)= 0

The maximum electric field occurs when r=rb.

4 0
3 years ago
Helppp meeee
worty [1.4K]
T = (v-0)/a
t = (45.5)/(9.8)
= 4.64m/s.

hope this helps :)
7 0
2 years ago
I need help please please thank you
Romashka [77]

Answer:

the first one is energy level

Explanation:

5 0
3 years ago
Susan works in the research and development department. She has recently purchased a large high-speed external drive and has att
ivann1987 [24]

     The reason why Susan's drive is not working is that she has connected the drive to a USB 2.0 port, which does not have enough power for her drive.

<h3>What is the USB?</h3>

USB is a short acronym for the original word called a Universal Serial Bus. USB is a connector interface for connecting a computer to peripherals and other devices.

USB comes in different specs such as the:

  • USB 2.0
  • USB 3.0

Some of the characteristics differences between USB 2.0 and 3.0 are:

A USB 2.0 requires 480 Mbps for data transfer speed while USB 3.0 requires 4800 Mbps.

A USB 2.0 has the ability to use a maximum power of 500 mA, while USB 3.0 can make use of up to 900 mA.

From the given information, It is stated that the drive requires a minimum of 400 Mbps and at least 900 mA;

Therefore, it implies that the drive is supposed to work with a power of at least 900 mA for it to work.

But since it is not working, we can conclude that the drive is connected to a USB 2.0 port (500 mA) which does not have enough power for the drive.

Learn more about the USB port here:

brainly.com/question/13714615

5 0
2 years ago
Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2
Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

F_n=F-F'

F_n=37.2-22.4

F_n=14.8\ N

Work done on the wagon is given by the product of net force and displacement. It is given by :

W=F_n\times d

W=14.8\ N\times 2.5\ m

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
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