Question

shannon dropped his ICP textbook. how fast was it going after 3 seconds? how far did it fall? please guys help mee quickly pleaseeee​

Answer 1

¡Hola!

For this problem, first, lets recabe information:

v = 0 m/s

t = 3 s

g = 9,82 m/s²

v' = ?

d = ?

First, for calculate the final velocity:

v' = v + g * t

v' = 0 m/s + 9,82 m/s² * 3 s

v' = 29,46 m/s $\leftarrow \boxed{\text{Velocity} }$

Now, for calculate how far did it fall:

d = v * t + g * t^2 / 2

Like v = 0 m/s, we can simplificate equation:

d = g * t^2 / 2

d = 9,82 m/s² * (3 s)^2 / 2

d = 9,82 m/s² * 9 s² / 2

d = 88,38 m / 2

d = 44.19  m $\leftarrow \boxed{\text{Distance} }$

¡Buena suerte!