Question

1- A 30 gram bullet travels at 300 m/s. How much kinetic energy does it have?

Answer 1

Answer:

1.35 kJ  

Explanation:

KE = ½mv² = ½ × 0.030  kg × (300 m·s⁻¹)² = 1350 J = 1.35 kJ

Answer 2

Given:-

• Mass (m) of the bullet = 30 grams
• Velocity of the bullet (v) = 300 m/s

To Find: Kinetic energy of the bullet.

We know,

Eₖ = ½mv²

where,

• Eₖ = Kinetic energy,
• m = Mass &
• v = Velocity.

thus,

Eₖ = ½(30 g)(300 m/s)²

= (15 g)(90000 m²/s²)

= 1350000 g m²/s²

= 1350 kg m²/s²

= 1350 J

= 1.35 kJ (Ans.)