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jolli1 [7]
3 years ago
12

2. Calculate the kinetic energy of a football being launched downfield by Patrick Mahomes. The football has a mass of .5 kg and

is thrown at a velocity of 25 m/s. Find the kinetic energy.​
Physics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

K.E = 156.25 Joules.

Explanation:

Given the following data;

Mass = 0.5kg

Velocity = 25 m/s

To find the kinetic energy;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

K.E = \frac{1}{2}0.5*25^{2}

K.E = 0.25 * 625

K.E = 156.25 Joules.

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An ideal parallel plate capacitor with a cross-sectional area of 0.4 cm2 contains a dielectric with a dielectric constant of 4 a
Mrrafil [7]

Answer: 283.2\times 10^{-9}\ nC

Explanation:

Given

Cross-sectional area A=0.4\ cm^2

Dielectric constant k=4

Dielectric strength E=2\times 10^8\ V/m

Distance between capacitors d=5\ mm

Maximum charge that can be stored before dielectric breakdown is given by

\Rightarrow Q=CV\\\\\Rightarrow Q=\dfrac{k\epsilon_oA}{d}\cdot (Ed)\quad\quad [V=E\cdot d]\\\\\Rightarrow Q=k\epsilon_oAE\\\\\Rightarrow Q=4\times 8.85\times 10^{-12}\times 0.4\times 10^{-4}\times 2\times 10^8\\\\\Rightarrow Q=28.32\times 10^{-8}\\\\\Rightarrow Q=283.2\times 10^{-9}\ nC

4 0
3 years ago
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How much current is in a circuit that includes a 9-volt battery and a bulb with a resistance of 12 ohms?
Reil [10]

V = IR

Where v is voltage I is current and r is resistance

So

V = 9

R = 12

V/R = I

9/12 = I

I = 0.75 A

4 0
3 years ago
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What is the difference between a unit and a variable?
scoundrel [369]

Answer:

A case is an experimental unit. ... Another synonym is experimental unit. A variable is a characteristic that is measured and can take on different values. In other words, something that varies between cases.

Explanation:

7 0
3 years ago
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A 3.80-m-long, 500 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building
Virty [35]

Answer:

Explanation:

The question is ;

3.80 m-long, 500. kg steel beam extends horizontally from the point

where it has been bolted to the framework of a new building under

construction. A 67.0 kg construction worker stands at the far end of

the beam. What is the magnitude of the torque about the point where the beam is bolted into place?

Solution:

Here two torques are in action

a) torque T1 due to weight of worker at the edge of the beam - at center of the beam

b) torque T2 due to weight of the uniform beam - at the point where the beam is bolted

So we first calculate the torque produced due to weight of the worker;

We can see that;

Distance of worker from the center of the beam = 1.9m

Mass of the worker = 67 kg

Value of g= 9.8 m/sec2

T1=force × distance from point of rotation

Here force is weight of the worker which is = mass × g=67×9.8=656.6 N

So the torque is

T1= 656.6×1.9=12225.892 Nm

or

T1 = 12225.892 Nm

Now torque by the beam itself ;

Length of the beam from its center point to the bolt point = 1.9 m

Weight force of beam acting at center point= mass× g= 500×9.8=4900 N

Torque T2 at bolt point by the beam weight = weight of beam × length of beam from its center to the bolt point = 4900×1.9=9310 Nm

T2=9310Nm

So total torque = T1+T2= 12225.892+9310=21565.892 Nm

8 0
3 years ago
A 7.7cm length of straight wire run horizontally along a north south line . The wire carries a 3.45 current flowing northward th
Maurinko [17]

Answer:

F = 0.332 N in the east direction

Explanation:

Length, L = 7.7 cm = 7.7 * 0.01 = 0.077 m(along the north south)

Current, I = 3.45 A (northwards)

Magnetic field, B = 1.25 T (vertically upwards)

The magnitude of the force is given by, F = ILBsin90

F = 3.45 * 0.077 * 1.25 * 1

F = 0.332 N

The direction of the force is calculated using the Right Hand Thumb Rule:

It states that "Hold the wire carrying current in your right hand so that the thumb points along the wire in the direction of the current, then the fingers will encircle the wire in the direction of the lines of magnetic force."

Based on the Right Hand Thumb Rule, the magnetic force will act in the east direction

3 0
3 years ago
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