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vfiekz [6]
3 years ago
14

My brainly isn’t working. When i have a new notification, and I click on it, it takes me to a pop-up saying “Oops.. something’s

wrong, try again” anyone know how to fix this, or report a problem?
please help !
Physics
1 answer:
motikmotik3 years ago
3 0

Answer:

If you remember your username and password when you set up brianly. Uninstall it and then reinstall then put your information in. Then if that dont work send them a message telling them what's going on

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Hey what is you answering streak and what fact dose it say
Valentin [98]

Answer:

It’s 53:) Or - quit

Explanation:

That’s my strong streak

5 0
2 years ago
Read 2 more answers
I need helpppppp asap
asambeis [7]
It’s c because it’s not Control so that means that it would be broken and non fix able
5 0
3 years ago
A car (mass 1200 kg, speed 100 km/h) and a truck (mass 2800 kg, speed 50 km/h) are moving in the same direction along a highway.
Sloan [31]

Answer:

Speed of the wreck after the collision is 65 km/h

Explanation:

When a car hits truck and sticks together, the  collision would be totally inelastic.  Since the both the vehicles  locked  together, they have the same final velocity.

Mass of car  m_{1}=1200 kg

Mass of truck m_{2}=2800 kg

Initial speed of the car u_{1}=100 km /h

Initial speed  of the truck u_{2}=50 km /h

The final velocity of the wreck will be

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

since final speed are same, v_{1}=v_{2}=v

m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v

1200\times 100 +2800 \times 50 =(1200+2800)v\\v=\frac{260000}{4000} \\v=65 km/h

5 0
2 years ago
A car of mass m push = 1200 kg is capable of a maximum acceleration of 6.00 m / s 2 . If this car is required to push a stalled
motikmotik

1)

first you find the maxium force that the car can produce.

f=ma

Fmax=(1100kg)(6m/s^2)

then use f = ma again to find the accel with the passengers

Fmax=(1100kg +1650kg)(a)

=> a = (1100kg)(6m/s^2)/( 1100kg +1650kg)

= 2.4 m/s^2

4 0
2 years ago
Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.
LiRa [457]

Answer:

         Time - taken = 2.5 s

          deceleration= -8 m/s²

Solution:

            Given:

                     speed, v = 8 m/s

                 distance, d = 20m

                     

              To Find:

                     deacceleration = ?

               

               As we know speed is defined as

                          v = d/t

                plugging in the values

                          t =  20/ 8

                          t = 2.5s

                Now from deceleration formula

                        a =  - v/ t

                        a = - 20/ 2.5

                        a = - 8 m/s²

          Thus, the time taken and acceleration is 2.5 s and -8 m/s²

          respectively.

          Learn more about deceleration here:

                brainly.com/question/13354629

                       #SPJ4  

               

                       

             

7 0
2 years ago
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