Answer:
0.3814128 m
Explanation:
t = Time taken = 36 ms
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration = 60g
g = Acceleration due to gravity = 9.81 m/s²
The distance the person traveled is 0.3814128 m
Which light is most sensitive to the eyes?
1 answer:
You might be interested in
Answer:
Explanation:
Assuming this problem: "Part (a) of the figure attached shows a non-conducting rod with a uniformly distributed charge +Q. The rod forms a half circle with radius R and produces an electric field of magnitude Earc at its center of curvature P. If the arc is collapsed to a point at distance R from P (Figure b), by what factor is the magnitude of the electric field at P multiplied?"
On this case the charge density is given by this formula:
assuming a half circle
We can find the force acting on the x axis with this:
We can cnvert the integral using the symmetrical property:
And we can find the electric field like this:
And the electric field just by the charge is given by:
And if we find the ratio for the two electrical fields we got:
