Sport and exercise psychology
Explanation:
Here you study the psychological factors that are connected to your performance and contribution to sport, exercises and physical activities.Through application of psychological principles you can attain higher mental health and your performance will be enhanced. For example, you will be able to recognize times when you experience emotional states without without knowing the reasons or causes which is a concept of arousal attribution.Understanding your pattern of behavior and attitude builds up your personality making you distinctive.
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Sports and exercise psychology :brainly.com/question/1213874
Keywords : exercise, sports science, study , achievement motivation, arousal attribution, personal development.
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Answer:
speed =wavelenght x frequency
v=4.5 x 10 to the -7 x 667=0.3 x 10 to the -4 m/s
speed= distance/time
time=distance/speed
t=4 x 10 to the 16/0.3 x 10 to the -4=13.33 x 10 to the 20 seconds
Explanation:
Measured reading is 1.65 kg
actual reading was 1.72 kg
error in the reading is 1.72 - 1.65 = 0.07 kg
Now percentage error is given as
<em>so this is -4.1% error as the measured reading is less than the actual value</em>
Entirely horizontal.
An object will continue to travel with the same velocity unless an external force is applied.
There are no external forces acting in the horizontal direction (except air resistance but the is negligable) so the ball will move in the horizonontal direction with with same speed at all times.
Force of gravity is acting downwards, meaning it is constantly acelleraring at 9.8ms^-2 towards the ground. When the ball reaches its heighest point, it is where the ball has stopped moving up and starts to move down, therfore it is not moving vertically at all.
Answer: a) angular acceleration(alpha)=-14.8rad/s^2
b) time taken (t) = 1.52s
Explanation:
What we are given
Mass of the solid sphere m =225g = 0.225kg
Diameter D = 3.00cm = 0.0300m
Radius = D/2 = 0.01500m
Frictional Force = 0.0200N
a) to determine the angular acceleration, we first calculate the torque, then moment of inertia, before the angular acceleration.
Torque = -fr
= - (0.0200)(0.01500)
=-3.00X10^-4Nm
Moment of inertia I
= 2/5mr^2
=2/5(0.225)(0.01500)^2
=2.025X10^-5kgm^2
Angular acceleration (alpha)= torque/moment of inertia (I)
= -3.00X10^-4Nm/2.025X10^-5kgm^2
=-14.8rad/s^2
b) time taken (∆t) = w/alpha
w= -22.5rad/s
Angular acceleration (alpha) = -14.8rad/s^2
∆t = -22.5/-14.8
= -1.52s
