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lorasvet [3.4K]
3 years ago
12

Metals can be described as

Physics
1 answer:
shutvik [7]3 years ago
7 0

They tend to be lustrous, ductile, malleable, and good conductors of electricity, while nonmetals are generally brittle (for solid nonmetals), lack lustre, and are insulators.

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There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted s
Maslowich

Answer:

.a = 849.05 m / s²

Explanation

The centripetal acceleration is

            a = v² / r

     

Linear and angular velocity are related

          v = w r

Angular velocity and frequency are related by

        w = 2π f

Let's replace

        a = w² r

         a = 4π² f² r

Let's reduce to the SI system

       f = 2.30 rev / s (2π rad / 1 rev) = 14.45 rad / s

       .r = 10.3 cm = 0.103 m

Let's calculate

       a = 4π² 14.45²  0.103

       .a = 849.05 m / s²

8 0
3 years ago
Will give brainliest! how does an engineer use physical science?
pentagon [3]

Answer: gravity, circuits

Explanation:

3 0
3 years ago
When heat is added to an object, what is happening to the item at the atomic level? (Check all that apply)
3241004551 [841]

Answer:

a

Explanation:

heat is energy, energy cannot be made or destroyed but transferred

6 0
3 years ago
Read 2 more answers
A student performed the following steps to find the solution to the equation x^2-2x-15=0 Where did the student go wrong? STEP 1:
AveGali [126]
B. In step 3

They incorrectly solved for x. It should have been x=-3 and x=5
3 0
3 years ago
3.00 textbook rests on a frictionless, horizontal tabletop surface. A cord attached to the book passes over a pulley whose diame
sammy [17]

Answer:

a1 = 3.56 m/s²

Explanation:

We are given;

Mass of book on horizontal surface; m1 = 3 kg

Mass of hanging book; m2 = 4 kg

Diameter of pulley; D = 0.15 m

Radius of pulley; r = D/2 = 0.15/2 = 0.075 m

Change in displacement; Δx = Δy = 1 m

Time; t = 0.75

I've drawn a free body diagram to depict this question.

Since we want to find the tension of the cord on 3.00 kg book, it means we are looking for T1 as depicted in the FBD attached. T1 is calculated from taking moments about the x-axis to give;

ΣF_x = T1 = m1 × a1

a1 is acceleration and can be calculated from Newton's 2nd equation of motion.

s = ut + ½at²

our s is now Δx and a1 is a.

Thus;

Δx = ut + ½a1(t²)

u is initial velocity and equal to zero because the 3 kg book was at rest initially.

Thus, plugging in the relevant values;

1 = 0 + ½a1(0.75²)

Multiply through by 2;

2 = 0.75²a1

a1 = 2/0.75²

a1 = 3.56 m/s²

6 0
3 years ago
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