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photoshop1234 [79]
2 years ago
12

Fernanda is working on a physics project. she is experimenting by rolling a marble down a ramp and then seeing how far it rolls

along the floor after leaving the ramp. which would be the dependent variable in fernanda’s experiments? the angle of the ramp the length of the ramp the distance the marble rolls after the ramp the direction that gravity makes the marble roll
Physics
1 answer:
Ratling [72]2 years ago
5 0

The distance covered on the floor after leaving the ramp is the dependent variable.

  • As a result of the marble's size, the substance it is constructed of, and the angle at which it is placed onto the ground, the distance it rolls varies.
  • Therefore, the angle at which the marble is released onto the ground, the type of material used to make the stone, or its size can all be considered independent variables.
<h3>What is Independent variable?</h3>
  • There are independent and dependent variables in every experiment.
  • A variable is considered independent if its change is not influenced by the change in another variable or factor.
<h3>What is Dependent variable?</h3>

In any experiment, the dependent variable must be measured or determined, and it must change as the independent variable does.

Learn more about independent and dependent variable here:

brainly.com/question/1479694

#SPJ4

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Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by
mylen [45]

Answer:

<em>I must travel with a speed of 2.97 x 10^8 m/s</em>

Explanation:

Sine the spacecraft flies at the same speed in the to and fro distance of the journey, then the time taken will be 6 months plus 6 months

Time that elapses on the spacecraft = 1 year

On earth the people have advanced 120 yrs

According to relativity, the time contraction on the spacecraft is gotten from

t = t_{0} /\sqrt{1 - \beta ^{2} }

where

t is the time that elapses on the spacecraft = 120 years

t_{0} = time here on Earth = 1 year

\beta is the ratio v/c

where

v is the speed of the spacecraft = ?

c is the speed of light = 3 x 10^8 m/s

substituting values, we have

120 = 1/\sqrt{1 - \beta ^{2} }

squaring both sides of the equation, we have

14400 = 1/(1 - \beta ^{2} )

14400 - 14400\beta ^{2} = 1

14400 - 1 = 14400\beta ^{2}

14399 = 14400\beta ^{2}

\beta ^{2} =  14399/14400 = 0.99

\beta = \sqrt{0.99} = 0.99

substitute β = v/c

v/c = 0.99

but c = 3 x 10^8 m/s

v = 0.99c = 0.99 x 3 x 10^8 = <em>2.97 x 10^8 m/s</em>

6 0
3 years ago
Martine also has an eraser.it has a mass of 3g,and a volume if 1cm3.what is its density
shtirl [24]

Answer:

3g/cm³

Explanation:

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<em>Substitute (plug in) the values:</em>

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Given that ;

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A= area = 4cm² = 0.0004 m²

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