How many grams of AgNO3 are needed to prepare a 0.25 m solution in 500 grams of water?
1 answer:
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Answer:
<h2>1.89 atm</h2>Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>1.89 atm</h3>Hope this helps you