<u>Explanation:</u>
In an electrochemical cell, two half electrochemical processes occur. One of which is oxidation process and other is reduction process.
Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
Oxidation half reaction occurs at anode and reduction half reaction occurs at cathode.
Half reaction of the overall reaction represents the two processes which occur inside the cell which is oxidation and reduction.
Think it would have to be
C)
Hope this is right
In order to answer this, you need to find the empirical data for the standard entropies. Please refer to this link: http://www.mrbigler.com/misc/energy-of-formation.PDF
For NO₂ gas, the entropy is 240 J/mol-K. For N₂O₄ gas, the entropy is 304.2 J/mol-K. Therefore, <em>the statement is false.</em>
Answer:NaF is ionic. NF3 is covalent. SiF4 is ionic. CaF2 is Ionic and NH4F is also ionic. Ionic compounds transfer electrons whereas covalent compounds share electrons hence the word "co". Also, ionic compounds are formed with metal and nonmetal. Where a covalent is with 2 nonmetals. Only ionic compounds would produce fluoride in water because ionic compounds can dissolve in water and covalent compounds cant.
Answer:
D) Rate = K [NO2][Cl2]
Explanation:
2 NO2 + Cl2 → 2 NO2Cl (overall reaction)
NO2 + Cl2 → NO2Cl + Cl (slow)
NO2 + Cl → NO2Cl (fast)
The rate-determining step is the slowest step in a reaction mechanism. Because it is the slowest, it determines the rate of the overall reaction.
Rate of reaction is typically given as;
Rate = K [Reactants]
In the slow step i the reaction mechanism, the reactants are; NO2 and Cl2. Since both are not intermediates, there is no need for further working out.
Rate = K [NO2][Cl2]
