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alekssr [168]
2 years ago
11

Draw the structure with the molecular formula C6H14O that most likely produced the below IR and 1H NMR. The 13C NMR data is 78.3

ppm, 43.9 ppm, 27.3 ppm, 13.3 ppm.

Chemistry
1 answer:
spayn [35]2 years ago
8 0

Answer:

                   The answer is 2,3-dimethylbutan-2-ol and the structure is attached below.

Explanation:

                     Although we are not provided with ¹H-NMR spectrum and IR spectrum but still we can elucidate the ¹³C-NMR data and finalize a plausible structure.

                      First of all we look at the molecular formula, we can conclude from the formula that the structure given is saturated in nature because the hydrogen deficiency index of this formula is zero. Hence, we can say that there is no double bond either between Carbon atoms or between carbon and oxygen atom. This can also be proved by the absence of peaks in downfield as unsaturated compounds and carbonyl compounds give value above 100 and 200 ppm respectively.

                      Secondly, we can also conclude that among the six carbon atom two pairs of them are having same electronic environment because we are having only 4 signals hence we can conclude that two pairs have same chemical shift values.

                       Also, after making every possinble isomer of given molecular formula the structure of 2,3-dimethylbutan-2-ol was found to be the most accurate structure.

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Atoms of elements that are in group 15 with what charge
liq [111]

Answer:

The elements in group 13 and group 15 form a cation with a -3 charge each.

8 0
2 years ago
For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that w
Sindrei [870]

Answer:

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K)(Vaq/Vo)], where

x = mass extracted

m = total mass of solute

K = distribution coefficient

Vo = volume of organic layer

Vaq = volume of aqueous layer

Data:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K)(Vaq/Vo) = 1  + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62  

x = m/1.62 = 0.618m

So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

Let r = the amount remaining after n extractions. Then  

r = m(0.382)^n.

If n = 7,

r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg

m = 75 - 0.088 = 75 mg

After seven extractions, 75 mg (99.999 %) of the solute will be extracted.

5 0
3 years ago
Positron Emission Tomography (PET) is an advanced medical scanning technique. Fluorine-18 is a commonly used isotope for PET sca
TiliK225 [7]

Answer:

Option D. equation D

Explanation:

Positron is simply a beta plus decay or superscript 0 e subscription 1 (0 1 e).

Now, let us consider the options given:

Option A is emitting alpha decay

Option B is emitting beta minus decay.

Option C is emitting beta minus decay.

Option D is emitting beta plus decay also known as Positron.

3 0
3 years ago
The majority of Canada’s manufacturing takes place in the provinces of Ontario and __________.
nikklg [1K]
C. Quebec hope this helps :)
6 0
2 years ago
Read 2 more answers
In the chemical reaction:Br2(g) + Cl2(g) ⇌ 2 BrCl(g) KP = 0.150If there is initially 0.500 atm of BrCl and nothing else in a con
klemol [59]

Answer:

The partial pressure of BrCl at equilibrium is 0.08 atm.

Explanation:

The equilibrium constant of the reaction is given by =K_p=0.150

Br_2(g) + Cl_2(g)\rightleftharpoons 2 BrCl(g)

initial

0       0         0.500 atm

At equilbrium

p      p       (0.500-2p)

The equilibrium constant's expression of the reaction is given by ;

 K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}

0.150=\frac{(0.500-2p)^2}{p\times p}

Solving for p:

p = 0.21 atm

The partial pressure of BrCl at equilibrium is:

(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]

7 0
3 years ago
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