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alekssr [168]
3 years ago
11

Draw the structure with the molecular formula C6H14O that most likely produced the below IR and 1H NMR. The 13C NMR data is 78.3

ppm, 43.9 ppm, 27.3 ppm, 13.3 ppm.

Chemistry
1 answer:
spayn [35]3 years ago
8 0

Answer:

                   The answer is 2,3-dimethylbutan-2-ol and the structure is attached below.

Explanation:

                     Although we are not provided with ¹H-NMR spectrum and IR spectrum but still we can elucidate the ¹³C-NMR data and finalize a plausible structure.

                      First of all we look at the molecular formula, we can conclude from the formula that the structure given is saturated in nature because the hydrogen deficiency index of this formula is zero. Hence, we can say that there is no double bond either between Carbon atoms or between carbon and oxygen atom. This can also be proved by the absence of peaks in downfield as unsaturated compounds and carbonyl compounds give value above 100 and 200 ppm respectively.

                      Secondly, we can also conclude that among the six carbon atom two pairs of them are having same electronic environment because we are having only 4 signals hence we can conclude that two pairs have same chemical shift values.

                       Also, after making every possinble isomer of given molecular formula the structure of 2,3-dimethylbutan-2-ol was found to be the most accurate structure.

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stepan [7]

Answer:

Low pressure

Explanation:

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8 0
3 years ago
True or false most materials occur in nature as pure substances
polet [3.4K]

Answer:

false

Explanation:

you rarely ever find a material as

a pure substance

5 0
4 years ago
It is desired to make 1.00 liter of 6.00 M nitric acid from concentrated 16.00 M HNO3.A) How many moles of nitric acid are in 1.
natima [27]

Answer:

A) 6.00 mol.

B) 0.375 L or 375 mL

C) 6.00 M

Explanation:

Hello,

A) In this case, from the definition of molarity, we compute the moles for the given volume and concentration:

n=M*V=1.00L*6.00mol/L=6.00mol

B) In this case, from the stock solution, the required volume is:

V=\frac{6.00mol}{16.00mol/L}=0.375L

C) In this case, we apply the following formula for dilution process:

M_1V_1=M_2V_2

Thus, solving for the final molarity, we obtain:

M_2=\frac{M_1V_1}{V_2}=\frac{16.00M*0.375L}{1.00L}\\  \\M_2=6.00M

Regards.

5 0
3 years ago
A 125.0 mg sample of an unknown, monoprotic acid was dissolved in 100.0 mL of distilled water and titrated with a 0.050 M soluti
Katarina [22]

Im honestly not really sure ..

i just need points

im sorry

6 0
4 years ago
HELP WITH THIS EASY SCIENCE WORK
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Explanation:

8 0
3 years ago
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