How many protons does silicon have? <br> a. 2 <br> b. 14 <br> c. 28 <br> d. 28.08

GREYUIT [131]

Answer:

<em>atomic number, the number of a chemical element in the periodic system, whereby the elements are arranged in order of increasing number of protons in the nucleus. Accordingly, the number of protons, which is always equal to the number of electrons in the neutral atom, is also the atomic number.</em>

Explanation:

<h3>brainlist please</h3>

4 0

3 years ago

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In nematode worms, a gene that codes for an ATPase has two alternatives for exon 4 and three alternatives for exon 7. How many d

Artyom0805 [142]

Answer:

6 different forms of the protein could be made.

Explanation:

For the given nematode worm, 6 different forms of the protein could be made. This is because of the alternative splicing that will produce 6 kinds of mRNAs. We have 2 different forms for the exon 4 while we have 3 differen forms for the exon 7. Therefore, we have a total of (2*3) 6 different forms of the protein for the given nematode worm.

4 0

4 years ago

When a neat, ordered chemical is changed into a more disordered chemical, there is an increase in what?

polet [3.4K]

When a neat, ordered chemical is change into a more disordered chemical, then there is an increase in ENTROPY.
Entropy refers to the degree of disorderliness in a reacting system. The degree of entropy is considered to be zero, when there is no disorderliness. The degree of entropy increases as the disorderliness increases. <span />

7 0

3 years ago

The theoretical yield of NaBr from

Lapatulllka [165]

Taking into account definition of percent yield, the percent yield for the reaction is 100%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 FeBr₃ + 3 Na₂S → Fе₂S₃ + 6 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

FeBr₃: 2 moles
Na₂S; 3 moles
Fе₂S₃: 1 mole
NaBr: 6 moles

<h3>Moles of NaBr formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 2 moles of FeBr₃ form 6 moles of NaBr, 2.36 moles of FeBr₃ form how many moles of NaBr?

$moles of NaBr=\frac{2.36 moles of FeBr_{3}x6 moles of NaBr }{2 moles of FeBr_{3}}$

moles of NaBr= 7.08 moles

Then, 7.08 moles of NaBr can be produced from 2.36 moles of FeBr₃.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

$percent yield=\frac{actual yield}{theorical yield}x100$

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield for the reaction in this case</h3>

In this case, being the molar mass of NaBr 102.9 g/mole, you know: