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4 years ago

What is the difference between Nuclear Fission and Nuclear Fusion? Also any examples of them

Chemistry

1 answer:

stealth61 [152]4 years ago

6 0

Answer:

Hiya there!

Explanation:

Both fission and fusion are nuclear reactions that produce energy, but the applications are not the same. Fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and fusion is the process where two light nuclei combine together releasing vast amounts of energy.

For example, uranium can fission to yield strontium and krypton. Fusion joins atomic nuclei together. The element formed has more neutrons or more protons than that of the starting material. For example, hydrogen and hydrogen can fuse to form helium.

Hope this helped! :D

Credit sourced from "nuclear.duke-energy.com, thoughtco.com"

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A student determines the value of the equilibrium constant to be 1.5297 x 107 for the following reaction: HBr(g) + 1/2 Cl2(g) --

Gennadij [26K]

Answer:

$\Delta G=-97.14kJ$

Explanation:

Hello,

In this case, the relationship between the equilibrium constant and the Gibbs free energy of reaction is:

$\Delta G=-RTln(K)$

Hence, we compute it as required:

$\Delta G=-8.314\frac{J}{mol\times K}*298K*ln(1.5297x10^7)\\\\\Delta G=-40.99kJ/mol$

And for 2.37 moles of hydrogen bromide, we obtain:

$\Delta G=-40.99kJ/mol*2.37mol\\\\\Delta G=-97.14kJ$

Best regards.

7 0

3 years ago

What is the difference between a compound and a mixture?

nataly862011 [7]

In order: B, D, A, A, A. C, A

7 0

3 years ago

What are the products of the alkali metals in a reaction with: oxygen, water, halogen?

slava [35]

Answer:

Using The element calcium Ca, we have

CaO

CaOH

CaCl

Explanation:

8 0

3 years ago

Read 2 more answers

HELP ASAP PLS Reactions, products and leftovers

Alenkasestr [34]

Answer:

See the answer below

Explanation:

From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.

Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.

Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.

In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover.

3 0

3 years ago

Please help me with this one. I think it’s right but can someone double check it.

devlian [24]

I think so because I did this before

6 0

3 years ago