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Elina [12.6K]
3 years ago
13

What is the radius and diameter of the following circle

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0

Answer:

Radius=16 cm Diameter=32 cm (let me know if it is for some reason incorrect)

Step-by-step explanation:

Diameter (just multiply the radius by 2)=32 cm

Radius (the length from the perimeter to the center)=16 cm

brilliants [131]3 years ago
3 0

Answer:

Radius: 16cm

Diameter: 32cm

Step-by-step explanation: Diameter 2 times the radius. Pls give me brainliest

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sin alpha = 7/25, alpha lies in quadrant ii, and cos beta = 2/5, beta lies in quadrant i. find cos(alpha-beta).
Ilia_Sergeevich [38]

Answer:

Therefore \cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}

Step-by-step explanation:

Given values are

\sin \alpha=\frac{7}{25}

\cos \beta=\frac{2}{5}

\sin^2x+\cos^2=1

\cos \alpha=\sqrt{1-\sin^2\alpha}

\cos \alpha=\sqrt{1-(\frac{7}{25})^2}

\cos \alpha=\sqrt{1-\frac{49}{625}}

\cos \alpha=\sqrt{\frac{576}{625}}

\cos \alpha=\frac{24}{25}

\sin \beta=\sqrt{1-\cos^2\beta}

\sin \beta=\sqrt{1-(\frac{2}{5})^2}

\sin \beta=\sqrt{1-\frac{4}{25}}

\sin \beta=\frac{\sqrt{21}}{5}

\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta

\cos(\alpha-\beta)=\frac{24}{25}\times\frac{2}{5}+\frac{7}{25}\times\frac{\sqrt{21}}{5}

\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}

7 0
3 years ago
-X-5y + z = 17
grin007 [14]

Answer:

x = -1 , y = -4 , z = -4

Step-by-step explanation:

Solve the following system:

{-x - 5 y + z = 17 | (equation 1)

-5 x - 5 y + 5 z = 5 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Swap equation 1 with equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

-x - 5 y + z = 17 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Subtract 1/5 × (equation 1) from equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 1 by 5:

{-x - y + z = 1 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 2 by 4:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Add 2 × (equation 1) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

0 x+3 y - z = -8 | (equation 3)

Swap equation 2 with equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x - y+0 z = 4 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z/3 = 4/3 | (equation 3)

Multiply equation 3 by 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z = 4 | (equation 3)

Multiply equation 3 by -1:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 3 to equation 2:

{-x - y + z = 1 | (equation 1)

0 x+3 y+0 z = -12 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Divide equation 2 by 3:

{-x - y + z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 2 to equation 1:

{-x + 0 y+z = -3 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Subtract equation 3 from equation 1:

{-x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Collect results:

Answer: {x = -1 , y = -4 , z = -4

8 0
3 years ago
kelli and her faimly went to the beach for a vacation. they drove 293 miles 7 hours to get theredid they drive each hour
Inessa [10]
Ok so, Since Kelli and her family drove a total of 293 miles in 7 hours, then your equation should be \frac{293miles}{7hrs} 
Now, since you have your ratio you divide 293 by 7 in order to get how many miles were driven in one hour
\frac{293}{7} = 41.85714286 miles/hr
5 0
3 years ago
Read 2 more answers
The graph shows the cube root parent function.
diamong [38]

Considering the graph of the cube root parent function, it is found that the correct statement is given by:

D. It is always increasing.

<h3>When a function is increasing?</h3>

A function is increasing when the vertical axis of the graph gets higher as we move the horizontal axis from left to right.

In this problem, the above statement is true for the entire function, hence option D is correct.

More can be learned about functions at brainly.com/question/25537936

#SPJ1

8 0
2 years ago
HELP HELP HELP LLEASE!!!!
Luda [366]

Answer:

1/9

Step-by-step explanation:

Only 1 out of the 9 options has the double pepperoni outcome

7 0
3 years ago
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