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3 years ago

The acceleration of gravity on the earth is 9.80 m/s 2. If a person weighs 335 N, what is his/her mass?

Physics

1 answer:

padilas [110]3 years ago

5 0

Answer:

About 34.18kg

Explanation:

Using F=ma, you know that the force that an object exerts can be found by multiplying the mass and the acceleration. Therefore, you can find the mass with the formula $m=\dfrac{F}{a}$ . Plugging in the values you were given, $m=\dfrac{335}{9.80}\approx 34.18kg$ . Hope this helps!

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At time t=0 a grinding wheel has an angular velocity of 28.0 rad/s . It has a constant angular acceleration of 35.0 rad/s2 until

notsponge [240]

Answer:

a). $x_{t}=583.3rad$

b). $t_{total}=10.52s$

c). $a=12.62 \frac{rad}{s^2}$

Explanation:

The angular acceleration is constant so we can use the formulas of uniform motion with the model of angular acceleration

a).

$x_{r}=x_{i}+v_{i}+\frac{1}{2}a_{a}*t^2$

$x_{r}=0+28.0\frac{rad}{s}*2.20s+\frac{1}{2}*35.0\frac{rad}{s^2}*2.20s$

$x_{r}=146.3rad$

so the total angle between t=0 and the time it stopped is

$x_{t}=146.3rad+437rad=583.3rad$

b).

$w_{f}=w_{o}+a*t$

$w_{f}=28.0rad/s+35rad/s^2*2.2s=105rad/s$ = $w_{o}$

$x_{t}-x_{r}=\frac{1}{2}*(w_{o}-w_{f})*t$

$583.3-146.3=\frac{1}{2}*(105-0)*t$

$t=\frac{437rad}{105\frac{rad}{s}}=8.32s$

$t_{total}=8.32+2.2=10.52s$

c).

$w_{f}=w_{o}+a*t$

$0=105 rad/s+a*8.32s$

$a=\frac{105 rad/s}{8.32s}$

$a=12.62 \frac{rad}{s^2}$

7 0

3 years ago

what moon phase will occur about 14 days after a first quarter?

garik1379 [7]

Answer:

waxing gibbous is the answer.

3 0

3 years ago

During the motion of the slinky in a transverse wave, what do the particles of the slinky coil do?

Mazyrski [523]

Answer:

C.) The slinky particles move up and down

Explanation:

Transverse Wave-

A wave that has a disturbance perpendicular to the wave motion

Hello! This is the correct answer! Have a blessed day! :)

If you are in K12, please review the lesson! :) It will give you some very helpful definitions! I hope this helped!

5 0

3 years ago

Suppose the original segment of wire is stretched to 10 times its original length. How much charge must be added to the wire to

Debora [2.8K]

Here we want to study how the linear charge density changes as we change the measures of our body.

We will find that we need to add 9*Q of charge to keep the linear charge density unchanged.

I will take two assumptions:

The charge is homogeneous, so the density is constant all along the wire.

As we work with a linear charge density we work in one dimension, so the wire "has no radius"

Originally, the wire has a charge Q and a length L.

The linear charge density will be given by:

λ = Q/L

Now the length of the wire is stretched to 10 times the original length, so we have:

L' = 10*L

We want to find the value of Q' such that λ' (the linear density of the stretched wire) is still equal to λ.

Then we will have:

λ' = Q'/L' = Q'/(10*L) = λ = Q/L

Q'/(10*L) = Q/L

Q'/10 = Q

Q' = 10*Q

So the new charge must be 10 times the original charge, this means that we need to add 9*Q of charge to keep the linear charge density unchanged.

If you want to learn more, you can read:

brainly.com/question/14514975

6 0

3 years ago

This diagram shows particles that make up an atom. Which label BEST completes the diagram ?

worty [1.4K]

Answer: option A. strong nuclear force.

Explanation:

The diagram shows the subatomic particles inside the nucelous: protons and neutrons.

As you know, the protons are positively charged partilces inside the nucleous.

Being those particles charged with the same kind of charge they experiment electrostatic repulsion. So, how do you explain that they can stand together in such small space as it is the nucleous?

The responsible of keeping the subatomic particles together is the so called strong nuclear force.

Strong nuclear force or simply strong force is one of the four fundamental interactions or forces: i) gravitational, ii) electromagnetic, iii) weak nuclear force, and iv) strong nuclear force.

Strong nuclear force is the strongest force of nature and acts only in short distances as those inside the nucleous and is responsible for both the atraction among quarks and the atraction among protons to bind them together inside the atomic nucleous.

8 0

4 years ago