Answer:
In electromagnetic waves.
Explanation:
Energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.
Answer:
E = 420.9 N/C
Explanation:
According to the given condition:

where,
E = Magnitude of Electric Field = ?
v = speed of charge = 230 m/s
B = Magnitude of Magnetic Field = 0.61 T
θ = Angle between speed and magnetic field = 90°
Therefore,

<u>E = 420.9 N/C</u>
It is given that the length of blade of the turbine is 58 m.
During the motion, the turbine will undergo rotational motion. Hence the radius of the circle traced by the turbine is equal to the length of the blade.
Hence radius r = 58 m.
The frequency of the turbine [f] =14 rpm.
Here rpm stands for rotation per minute.
Hence the frequency of the turbine in one second-


Here Hz[ hertz] is the unit of frequency.
The angular velocity of the turbine 
radian/second
Now we have to calculate the centripetal acceleration of the blade.
Let the linear velocity of the blade is v.
we know that linear velocity v=ωr
The centripetal acceleration is calculated as-

![=\frac{[\omega r]^2}{r}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5B%5Comega%20r%5D%5E2%7D%7Br%7D)

![=[1.465124]^2 *58](https://tex.z-dn.net/?f=%3D%5B1.465124%5D%5E2%20%2A58)
[ans]
Answer:

Explanation:
Additional information:
<em>The ball has charge </em>
<em>, and the ring has positive charge </em>
<em> distributed uniformly along its circumference. </em>
The electric field at distance
along the z-axis due to the charged ring is

Therefore, the force on the ball with charge
is


and according to Newton's second law

substituting
we get:

rearranging we get:

Now we use the approximation that
<em>(we use this approximation instead of the original </em>
<em> since </em>
<em>, our assumption still holds )</em>
and get


Now the last equation looks like a Simple Harmonic Equation

where

is the frequency of oscillation. Applying this to our equation we get:


Answer:
D) surface area of the water
Explanation:
The pressure at the bottom of a column of fluid is given by Stevino's law:

where
p is the pressure at the bottom of the column
is the density
g is the acceleration due to gravity
h is the depth of the liquid
So, we see that the pressure at the bottom of a jug filled with water depends on all these quantities:
A) depth of the liquid
B) acceleration due to gravity
C) density of water
While it does not depend on:
D) surface area of the water