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ANTONII [103]
2 years ago
12

Will a precipitate form if you mix barium chloride and potassium carbonate?

Chemistry
1 answer:
kaheart [24]2 years ago
5 0

Potassium carbonate reacts with barium chloride to precipitate insoluble barium salts that is barium carbonate, when the solutions are mixed together you'll see white precipitate that is barium carbonate and potassium is dissolve in the solution to form potassium chloride.

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In performing this week's bromination reaction, if you were to start with 126 mg of acetanilide (135.17 g/mol), calculate the th
Artemon [7]

Answer:

Theoretical yield of C8H8BrNO:

In moles

0.000945

In grams

0.204

Explanation:

Theoretical yield of a reaction is defined as the quantity of the product obtained from the complete conversion of a limiting reactant in a chemical reaction. Theoretical yield can be expressed as grams or moles.

Equation of reaction:

C8H9NO + Br2 --> C8H8BrNO + HBr

Since C8H9NO is the limiting reagent, 1 mole of C8H9NO reacted to form 1 mole of C8H8BrNO

Mass of C8H9NO = 129 mg

= 0.129 g.

Molar mass of C8H9NO = 135.17 g/mol.

Number of moles of C8H9NO = mass/molar mass.

= 0.129/135.17

= 0.00095 moles of C8H9NO

Since 1 mole of C8H9NO yielded 1 mole of C8H8BrNO

Therefore, 0.000954 moles of C8H8BrNO

Theoretical yield (in grams) = molar mass * number of moles

= 214.06 * 0.00095

= 0.204 of C8H8BrNO

3 0
3 years ago
ASAP please
choli [55]
D.
0.220/0.2= 1.10 M
5 0
2 years ago
Which of the following is a galvanic cell?
sladkih [1.3K]

C. Aluminum (Al) oxidized, zinc (Zn) reduced

<h3>Further explanation</h3>

Given

Metals that undergo oxidation and reduction

Required

A galvanic cell

Solution

The condition for voltaic cells is that they can react spontaneously, indicated by a positive cell potential.

\large {\boxed {\bold {E ^ ocell = E ^ ocatode -E ^ oanode}}}

or:  

E ° cell = E ° reduction-E ° oxidation  

For the reaction to occur spontaneously (so that it E cell is positive), the  E° anode must be less than the E°cathode

If we look at the voltaic series:

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>

The standard potential value(E°) from left to right in the voltaic series will be greater, so that the metal undergoing an oxidation reaction (acting as an anode) must be located to the left of the reduced metal (as a cathode)

<em />

From the available answer choices, oxidized Al (anode) and reduced Zn (cathode) are voltaic/galvanic cells.

7 0
3 years ago
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