Oceanographer? I think that is what it is.
The final velocity of the 14 kg object is 1.6 m/s in the same direction
Explanation:
We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write
where:
is the mass of the first object
is the initial velocity of the first object
is the final velocity of the first object
is the mass of the second object
is the initial velocity of the second object
is the final velocity of the second object
Re-arranging the equation and substituting the values, we find:
And the direction is the same as the initial direction, since it has the same sign.
Learn more about conservation of momentum:
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Answer:
45 J
Explanation:
Assuming the level at which the ball is thrown upwards is the ground level,
We can use the equations of motion to obtain the maximum height covered by the ball and then calculate the potential energy
u = initial velocity of the ball = 3 m/s
h = y = vertical distance covered by the ball = ?
v = final velocity of the ball at the maximum height = 0 m/s
g = acceleration due to gravity = -9.8 m/s²
v² = u² + 2ay
0 = 3² + 2(-9.8)(y)
19.6y = 9
y = (9/19.6)
y = 0.459 m
The potential energy the ball will have at the top of its motion = mgh
mgh = (10)(9.8)(0.459) = 45 J
Hope this Helps!!!
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