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____ [38]
3 years ago
13

A reaction of 100mL of 1.35 M HCl and 100mL of 1.76 M NaOH is monitored and the following

Chemistry
1 answer:
uysha [10]3 years ago
6 0

Answer:  \Delta H for the reaction is 87935 J

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of HCl=Molarity\times {\text {Volume in L}}=1.35\times 0.01=0.135moles

moles of NaOH= Molarity\times {\text {Volume in L}}=1.76\times 0.01=0.176moles

As 1 mole of HCl neutralizes 1 mole of NaOH

0.135 moles of HCl will neutralize = 0.135 mole of NaOH

Thus HCl is the limiting reagent.

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Q = Heat absorbed by water = ?

m = mass of water = 200 g    (volume of water=200ml, density of wtaer = 1 g/ml)

c = specific heat capacity = 4.18 J/g^0C

Initial temperature of water = = 24.6°C

Final temperature of water=  = 38.8 °C

Q=200\times 4.18\times (38.8-24.6)

Q=11871.2J

Thus heat released by 0.135 moles is = -11871.2 J

heat released by 1 mole is =\frac{-11871.2 J}{0.135}\times 1=-87935J

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