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3 years ago

Why do some clusters of galaxies emit x-rays?

Physics

1 answer:

Alenkasestr [34]3 years ago

8 0

It may be the result of galaxy collisions. Hope that helped

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Which would exert the most gravity on a spacecraft that is passing close to Jupiter?

klio [65]

D. Jupiter has the highest amount of gravity in our solar system

7 0

2 years ago

5 A \machine produces compression waves in a spring that is 120 cm long by pulsing twice every second. The back and forth moveme

olga2289 [7]

The correct answer is C) frequency.
In fact, the frequency is the number of wave crests (or pulses) per seconds. In our problem, the machine that produces the wave pulses two times per second, so this is exactly the frequency of the compression wave.

7 0

3 years ago

Read 2 more answers

An investigator collects a sample of a radioactive isotope with an activity of 490,000 Bq.48 hours later, the activity is 110,00

Daniel [21]

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ $A = A_0 e^{- \lambda t}$

or,

⇒ $\frac{A}{A_0}=e^{-\lambda t}$

By taking "ln", we get

⇒ $ln \frac{A}{A_0}=- \lambda t$

By substituting the values, we get

⇒ $-ln \frac{110000}{490000} = -48 \lambda$

⇒ $-1.4939=-48 \lambda$

$\lambda = 0.031122$

As,

⇒ $\lambda = \frac{ln_2}{\frac{T}{2} }$

then,

⇒ $\frac{ln_2}{T_ \frac{1}{2} } =0.031122$

⇒ $T_\frac{1}{2}=\frac{ln_2}{0.031122}$

$=22.27 \ hours$

3 0

2 years ago

Did changing the angle of the incline affect the following parameters?

MArishka [77]

Increasing the level of an incline:
Increases final velocity
Increases the work done
Increases the initial potential energy
Increases the final kinetic energy

4 0

3 years ago

A volcanic eruption melts a large area of rock, and all gases are expelled. after cooling, 40ar (atomic number 18) accumulates f

chubhunter [2.5K]

Decay of Ar-40 produces 1.33 mmol of K-40. Remaining number of moles of Ar-40 is 1.50 mmol. Initial mmol of Ar-40 present will be sum of number of moles of K-40 and remaining number of moles of Ar-40.

$n_{Ar-40}=(1.33+1.50)m mol=2.83 mmol$