Answer:
B is the best answer for this question
A radio station broadcast on a frequency of 3.7 mhz what is the energy of the radio wave A radio station broadcasts its programmes at a wavelength of 500 m. Find the frequency of the radiowaves transmitted by the radio station, if the speed of radiowaves in air is 3 x 108 m/s. Ans: 6 x 10 Hz
<h3>What is
radio station ?</h3>
Radio broadcasting is the act of sending audio (sound), occasionally together with accompanying metadata, across radio waves to radio receivers used by the general public. Unlike satellite radio, which uses a satellite in Earth's orbit, terrestrial radio broadcasting uses a land-based radio station to transmit radio waves. The listener needs a broadcast radio receiver to hear the material (radio). A radio network with which stations frequently have affiliations provide content in a standard radio format, whether through broadcast syndication, simulcasting, or both. Radio stations use a variety of modulations to transmit their signals, including FM (frequency modulation), which is an older analog audio standard, and AM (amplitude modulation).
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Answer:
direction, speed
means the object is staying still, 0
newtons, N
the sum of all the forces acting on an object
Explanation:
Given:
mass is 3.1 kilograms
The acceleration due to gravity
is 9.8m/s2
Required:
Weight
Solution:
W = mg
W = (3.1 kilograms)( 9.8m/s2)
W = 30.38 Newtons
The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
<h3>What current flows through the bulb as well as the power of the bulb?</h3>
From ohm's law; V = I × R
Where V is the voltage, I is the current and R is the resistance.
Also, Power is expressed as; P = V × I
Where V is voltage and I is current.
Given that;
- Resistance R = 10.0 ohms
- Voltage V = 12.0V
- Current I = ?
- Power P = ?
First, we determine the current flow through the bulb.
V = I × R
12.0V = I × 10.0 ohms
I = 12.0 ÷ 10.0
I = 1.2A
Next, we determine the power of the bulb.
P = V × I
P = 12.0V × 1.2A
P = 14.4 Watts
Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
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